Metamath Proof Explorer


Theorem acufl

Description: The axiom of choice implies the ultrafilter lemma. (Contributed by Mario Carneiro, 26-Aug-2015)

Ref Expression
Assertion acufl CHOICEUFL=V

Proof

Step Hyp Ref Expression
1 vex xV
2 1 pwex 𝒫xV
3 2 pwex 𝒫𝒫xV
4 dfac10 CHOICEdomcard=V
5 4 biimpi CHOICEdomcard=V
6 3 5 eleqtrrid CHOICE𝒫𝒫xdomcard
7 numufl 𝒫𝒫xdomcardxUFL
8 6 7 syl CHOICExUFL
9 1 a1i CHOICExV
10 8 9 2thd CHOICExUFLxV
11 10 eqrdv CHOICEUFL=V