Metamath Proof Explorer


Theorem addccncf2

Description: Adding a constant is a continuous function. (Contributed by Glauco Siliprandi, 11-Dec-2019)

Ref Expression
Hypothesis addccncf2.1 ⊢ F = x ∈ A ⟼ B + x
Assertion addccncf2 ⊢ A ⊆ ℂ ∧ B ∈ ℂ → F : A ⟶cn ℂ

Proof

Step Hyp Ref Expression
1 addccncf2.1 ⊢ F = x ∈ A ⟼ B + x
2 simpl ⊢ A ⊆ ℂ ∧ B ∈ ℂ → A ⊆ ℂ
3 simpr ⊢ A ⊆ ℂ ∧ B ∈ ℂ → B ∈ ℂ
4 ssidd ⊢ A ⊆ ℂ ∧ B ∈ ℂ → ℂ ⊆ ℂ
5 2 3 4 constcncfg ⊢ A ⊆ ℂ ∧ B ∈ ℂ → x ∈ A ⟼ B : A ⟶cn ℂ
6 ssid ⊢ ℂ ⊆ ℂ
7 cncfmptid ⊢ A ⊆ ℂ ∧ ℂ ⊆ ℂ → x ∈ A ⟼ x : A ⟶cn ℂ
8 6 7 mpan2 ⊢ A ⊆ ℂ → x ∈ A ⟼ x : A ⟶cn ℂ
9 8 adantr ⊢ A ⊆ ℂ ∧ B ∈ ℂ → x ∈ A ⟼ x : A ⟶cn ℂ
10 5 9 addcncf ⊢ A ⊆ ℂ ∧ B ∈ ℂ → x ∈ A ⟼ B + x : A ⟶cn ℂ
11 1 10 eqeltrid ⊢ A ⊆ ℂ ∧ B ∈ ℂ → F : A ⟶cn ℂ