Metamath Proof Explorer


Theorem aibnbaif

Description: Given a implies b, not b, there exists a proof for a is F. (Contributed by Jarvin Udandy, 1-Sep-2016)

Ref Expression
Hypotheses aibnbaif.1 ⊢ φ → ψ
aibnbaif.2 ⊢ ¬ ψ
Assertion aibnbaif ⊢ φ ↔ ⊥

Proof

Step Hyp Ref Expression
1 aibnbaif.1 ⊢ φ → ψ
2 aibnbaif.2 ⊢ ¬ ψ
3 1 2 aibnbna ⊢ ¬ φ
4 3 bifal ⊢ φ ↔ ⊥