Metamath Proof Explorer


Theorem aisbnaxb

Description: Given a is equivalent to b, there exists a proof for (not (a xor b)). (Contributed by Jarvin Udandy, 28-Aug-2016)

Ref Expression
Hypothesis aisbnaxb.1 ⊢ φ ↔ ψ
Assertion aisbnaxb ⊢ ¬ φ ⊻ ψ

Proof

Step Hyp Ref Expression
1 aisbnaxb.1 ⊢ φ ↔ ψ
2 1 notnoti ⊢ ¬ ¬ φ ↔ ψ
3 df-xor ⊢ φ ⊻ ψ ↔ ¬ φ ↔ ψ
4 2 3 mtbir ⊢ ¬ φ ⊻ ψ