Metamath Proof Explorer


Theorem angcld

Description: The (signed) angle between two vectors is in ( -upi (,] pi ) . Deduction form. (Contributed by David Moews, 28-Feb-2017)

Ref Expression
Hypotheses ang.1 ⊢ F = x ∈ ℂ ∖ 0 , y ∈ ℂ ∖ 0 ⟼ ℑ ⁡ log ⁡ y x
angcld.1 ⊢ φ → X ∈ ℂ
angcld.2 ⊢ φ → X ≠ 0
angcld.3 ⊢ φ → Y ∈ ℂ
angcld.4 ⊢ φ → Y ≠ 0
Assertion angcld ⊢ φ → X F Y ∈ − π π

Proof

Step Hyp Ref Expression
1 ang.1 ⊢ F = x ∈ ℂ ∖ 0 , y ∈ ℂ ∖ 0 ⟼ ℑ ⁡ log ⁡ y x
2 angcld.1 ⊢ φ → X ∈ ℂ
3 angcld.2 ⊢ φ → X ≠ 0
4 angcld.3 ⊢ φ → Y ∈ ℂ
5 angcld.4 ⊢ φ → Y ≠ 0
6 1 2 3 4 5 angvald ⊢ φ → X F Y = ℑ ⁡ log ⁡ Y X
7 4 2 3 divcld ⊢ φ → Y X ∈ ℂ
8 4 2 5 3 divne0d ⊢ φ → Y X ≠ 0
9 7 8 logimclad ⊢ φ → ℑ ⁡ log ⁡ Y X ∈ − π π
10 6 9 eqeltrd ⊢ φ → X F Y ∈ − π π