Metamath Proof Explorer


Theorem argcj

Description: The argument of the conjugate of a complex number A . (Contributed by Thierry Arnoux, 5-Nov-2025)

Ref Expression
Hypotheses efiargd.1 ⊢ φ → A ∈ ℂ
efiargd.2 ⊢ φ → A ≠ 0
arginv.1 ⊢ φ → ¬ − A ∈ ℝ +
Assertion argcj ⊢ φ → ℑ ⁡ log ⁡ A ‾ = − ℑ ⁡ log ⁡ A

Proof

Step Hyp Ref Expression
1 efiargd.1 ⊢ φ → A ∈ ℂ
2 efiargd.2 ⊢ φ → A ≠ 0
3 arginv.1 ⊢ φ → ¬ − A ∈ ℝ +
4 simpr ⊢ φ ∧ A ∈ ℝ → A ∈ ℝ
5 2 adantr ⊢ φ ∧ A ∈ ℝ → A ≠ 0
6 3 adantr ⊢ φ ∧ A ∈ ℝ → ¬ − A ∈ ℝ +
7 rpneg ⊢ A ∈ ℝ ∧ A ≠ 0 → A ∈ ℝ + ↔ ¬ − A ∈ ℝ +
8 7 biimpar ⊢ A ∈ ℝ ∧ A ≠ 0 ∧ ¬ − A ∈ ℝ + → A ∈ ℝ +
9 4 5 6 8 syl21anc ⊢ φ ∧ A ∈ ℝ → A ∈ ℝ +
10 9 relogcld ⊢ φ ∧ A ∈ ℝ → log ⁡ A ∈ ℝ
11 10 reim0d ⊢ φ ∧ A ∈ ℝ → ℑ ⁡ log ⁡ A = 0
12 4 cjred ⊢ φ ∧ A ∈ ℝ → A ‾ = A
13 12 fveq2d ⊢ φ ∧ A ∈ ℝ → log ⁡ A ‾ = log ⁡ A
14 13 fveq2d ⊢ φ ∧ A ∈ ℝ → ℑ ⁡ log ⁡ A ‾ = ℑ ⁡ log ⁡ A
15 11 negeqd ⊢ φ ∧ A ∈ ℝ → − ℑ ⁡ log ⁡ A = − 0
16 neg0 ⊢ − 0 = 0
17 15 16 eqtrdi ⊢ φ ∧ A ∈ ℝ → − ℑ ⁡ log ⁡ A = 0
18 11 14 17 3eqtr4d ⊢ φ ∧ A ∈ ℝ → ℑ ⁡ log ⁡ A ‾ = − ℑ ⁡ log ⁡ A
19 1 adantr ⊢ φ ∧ ℑ ⁡ A = 0 → A ∈ ℂ
20 simpr ⊢ φ ∧ ℑ ⁡ A = 0 → ℑ ⁡ A = 0
21 19 20 reim0bd ⊢ φ ∧ ℑ ⁡ A = 0 → A ∈ ℝ
22 21 ex ⊢ φ → ℑ ⁡ A = 0 → A ∈ ℝ
23 22 necon3bd ⊢ φ → ¬ A ∈ ℝ → ℑ ⁡ A ≠ 0
24 23 imp ⊢ φ ∧ ¬ A ∈ ℝ → ℑ ⁡ A ≠ 0
25 logcj ⊢ A ∈ ℂ ∧ ℑ ⁡ A ≠ 0 → log ⁡ A ‾ = log ⁡ A ‾
26 1 24 25 syl2an2r ⊢ φ ∧ ¬ A ∈ ℝ → log ⁡ A ‾ = log ⁡ A ‾
27 26 fveq2d ⊢ φ ∧ ¬ A ∈ ℝ → ℑ ⁡ log ⁡ A ‾ = ℑ ⁡ log ⁡ A ‾
28 1 adantr ⊢ φ ∧ ¬ A ∈ ℝ → A ∈ ℂ
29 2 adantr ⊢ φ ∧ ¬ A ∈ ℝ → A ≠ 0
30 28 29 logcld ⊢ φ ∧ ¬ A ∈ ℝ → log ⁡ A ∈ ℂ
31 30 imcjd ⊢ φ ∧ ¬ A ∈ ℝ → ℑ ⁡ log ⁡ A ‾ = − ℑ ⁡ log ⁡ A
32 27 31 eqtrd ⊢ φ ∧ ¬ A ∈ ℝ → ℑ ⁡ log ⁡ A ‾ = − ℑ ⁡ log ⁡ A
33 18 32 pm2.61dan ⊢ φ → ℑ ⁡ log ⁡ A ‾ = − ℑ ⁡ log ⁡ A