Metamath Proof Explorer


Theorem asclf1

Description: Two ways of saying the scalar injection is one-to-one. (Contributed by SN, 3-Jul-2025)

Ref Expression
Hypotheses asclf1.a ⊢ A = algSc ⁡ W
asclf1.b ⊢ B = Base W
asclf1.s ⊢ S = Scalar ⁡ W
asclf1.k ⊢ K = Base S
asclf1.0 ⊢ 0 ˙ = 0 W
asclf1.n ⊢ N = 0 S
asclf1.r ⊢ φ → W ∈ Ring
asclf1.m ⊢ φ → W ∈ LMod
Assertion asclf1 ⊢ φ → A : K ⟶ 1-1 B ↔ ∀ s ∈ K A ⁡ s = 0 ˙ → s = N

Proof

Step Hyp Ref Expression
1 asclf1.a ⊢ A = algSc ⁡ W
2 asclf1.b ⊢ B = Base W
3 asclf1.s ⊢ S = Scalar ⁡ W
4 asclf1.k ⊢ K = Base S
5 asclf1.0 ⊢ 0 ˙ = 0 W
6 asclf1.n ⊢ N = 0 S
7 asclf1.r ⊢ φ → W ∈ Ring
8 asclf1.m ⊢ φ → W ∈ LMod
9 1 3 7 8 asclghm ⊢ φ → A ∈ S GrpHom W
10 4 2 6 5 ghmf1 ⊢ A ∈ S GrpHom W → A : K ⟶ 1-1 B ↔ ∀ s ∈ K A ⁡ s = 0 ˙ → s = N
11 9 10 syl ⊢ φ → A : K ⟶ 1-1 B ↔ ∀ s ∈ K A ⁡ s = 0 ˙ → s = N