Metamath Proof Explorer


Theorem asclply1subcl

Description: Closure of the algebra scalar injection function in a polynomial on a subring. (Contributed by Thierry Arnoux, 5-Feb-2025)

Ref Expression
Hypotheses asclply1subcl.1 ⊢ A = algSc ⁡ V
asclply1subcl.2 ⊢ U = R ↾ 𝑠 S
asclply1subcl.3 ⊢ V = Poly 1 ⁡ R
asclply1subcl.4 ⊢ W = Poly 1 ⁡ U
asclply1subcl.5 ⊢ P = Base W
asclply1subcl.6 ⊢ φ → S ∈ SubRing ⁡ R
asclply1subcl.7 ⊢ φ → Z ∈ S
Assertion asclply1subcl ⊢ φ → A ⁡ Z ∈ P

Proof

Step Hyp Ref Expression
1 asclply1subcl.1 ⊢ A = algSc ⁡ V
2 asclply1subcl.2 ⊢ U = R ↾ 𝑠 S
3 asclply1subcl.3 ⊢ V = Poly 1 ⁡ R
4 asclply1subcl.4 ⊢ W = Poly 1 ⁡ U
5 asclply1subcl.5 ⊢ P = Base W
6 asclply1subcl.6 ⊢ φ → S ∈ SubRing ⁡ R
7 asclply1subcl.7 ⊢ φ → Z ∈ S
8 eqid ⊢ Base R = Base R
9 8 subrgss ⊢ S ∈ SubRing ⁡ R → S ⊆ Base R
10 6 9 syl ⊢ φ → S ⊆ Base R
11 10 7 sseldd ⊢ φ → Z ∈ Base R
12 subrgrcl ⊢ S ∈ SubRing ⁡ R → R ∈ Ring
13 3 ply1sca ⊢ R ∈ Ring → R = Scalar ⁡ V
14 6 12 13 3syl ⊢ φ → R = Scalar ⁡ V
15 14 fveq2d ⊢ φ → Base R = Base Scalar ⁡ V
16 11 15 eleqtrd ⊢ φ → Z ∈ Base Scalar ⁡ V
17 eqid ⊢ Scalar ⁡ V = Scalar ⁡ V
18 eqid ⊢ Base Scalar ⁡ V = Base Scalar ⁡ V
19 eqid ⊢ ⋅ V = ⋅ V
20 eqid ⊢ 1 V = 1 V
21 1 17 18 19 20 asclval ⊢ Z ∈ Base Scalar ⁡ V → A ⁡ Z = Z ⋅ V 1 V
22 16 21 syl ⊢ φ → A ⁡ Z = Z ⋅ V 1 V
23 3 2 4 5 subrgply1 ⊢ S ∈ SubRing ⁡ R → P ∈ SubRing ⁡ V
24 eqid ⊢ V ↾ 𝑠 P = V ↾ 𝑠 P
25 24 19 ressvsca ⊢ P ∈ SubRing ⁡ V → ⋅ V = ⋅ V ↾ 𝑠 P
26 6 23 25 3syl ⊢ φ → ⋅ V = ⋅ V ↾ 𝑠 P
27 26 oveqd ⊢ φ → Z ⋅ V 1 V = Z ⋅ V ↾ 𝑠 P 1 V
28 id ⊢ φ → φ
29 20 subrg1cl ⊢ P ∈ SubRing ⁡ V → 1 V ∈ P
30 6 23 29 3syl ⊢ φ → 1 V ∈ P
31 3 2 4 5 6 24 ressply1vsca ⊢ φ ∧ Z ∈ S ∧ 1 V ∈ P → Z ⋅ W 1 V = Z ⋅ V ↾ 𝑠 P 1 V
32 28 7 30 31 syl12anc ⊢ φ → Z ⋅ W 1 V = Z ⋅ V ↾ 𝑠 P 1 V
33 27 32 eqtr4d ⊢ φ → Z ⋅ V 1 V = Z ⋅ W 1 V
34 2 subrgring ⊢ S ∈ SubRing ⁡ R → U ∈ Ring
35 4 ply1lmod ⊢ U ∈ Ring → W ∈ LMod
36 6 34 35 3syl ⊢ φ → W ∈ LMod
37 2 8 ressbas2 ⊢ S ⊆ Base R → S = Base U
38 6 9 37 3syl ⊢ φ → S = Base U
39 7 38 eleqtrd ⊢ φ → Z ∈ Base U
40 2 ovexi ⊢ U ∈ V
41 4 ply1sca ⊢ U ∈ V → U = Scalar ⁡ W
42 40 41 ax-mp ⊢ U = Scalar ⁡ W
43 eqid ⊢ ⋅ W = ⋅ W
44 eqid ⊢ Base U = Base U
45 5 42 43 44 lmodvscl ⊢ W ∈ LMod ∧ Z ∈ Base U ∧ 1 V ∈ P → Z ⋅ W 1 V ∈ P
46 36 39 30 45 syl3anc ⊢ φ → Z ⋅ W 1 V ∈ P
47 33 46 eqeltrd ⊢ φ → Z ⋅ V 1 V ∈ P
48 22 47 eqeltrd ⊢ φ → A ⁡ Z ∈ P