Metamath Proof Explorer


Theorem asinlem

Description: The argument to the logarithm in df-asin is always nonzero. (Contributed by Mario Carneiro, 31-Mar-2015)

Ref Expression
Assertion asinlem ⊢ A ∈ ℂ → i ⁢ A + 1 − A 2 ≠ 0

Proof

Step Hyp Ref Expression
1 ax-icn ⊢ i ∈ ℂ
2 mulcl ⊢ i ∈ ℂ ∧ A ∈ ℂ → i ⁢ A ∈ ℂ
3 1 2 mpan ⊢ A ∈ ℂ → i ⁢ A ∈ ℂ
4 ax-1cn ⊢ 1 ∈ ℂ
5 sqcl ⊢ A ∈ ℂ → A 2 ∈ ℂ
6 subcl ⊢ 1 ∈ ℂ ∧ A 2 ∈ ℂ → 1 − A 2 ∈ ℂ
7 4 5 6 sylancr ⊢ A ∈ ℂ → 1 − A 2 ∈ ℂ
8 7 sqrtcld ⊢ A ∈ ℂ → 1 − A 2 ∈ ℂ
9 3 8 subnegd ⊢ A ∈ ℂ → i ⁢ A − − 1 − A 2 = i ⁢ A + 1 − A 2
10 8 negcld ⊢ A ∈ ℂ → − 1 − A 2 ∈ ℂ
11 0ne1 ⊢ 0 ≠ 1
12 0cnd ⊢ A ∈ ℂ → 0 ∈ ℂ
13 1cnd ⊢ A ∈ ℂ → 1 ∈ ℂ
14 subcan2 ⊢ 0 ∈ ℂ ∧ 1 ∈ ℂ ∧ A 2 ∈ ℂ → 0 − A 2 = 1 − A 2 ↔ 0 = 1
15 14 necon3bid ⊢ 0 ∈ ℂ ∧ 1 ∈ ℂ ∧ A 2 ∈ ℂ → 0 − A 2 ≠ 1 − A 2 ↔ 0 ≠ 1
16 12 13 5 15 syl3anc ⊢ A ∈ ℂ → 0 − A 2 ≠ 1 − A 2 ↔ 0 ≠ 1
17 11 16 mpbiri ⊢ A ∈ ℂ → 0 − A 2 ≠ 1 − A 2
18 sqmul ⊢ i ∈ ℂ ∧ A ∈ ℂ → i ⁢ A 2 = i 2 ⁢ A 2
19 1 18 mpan ⊢ A ∈ ℂ → i ⁢ A 2 = i 2 ⁢ A 2
20 i2 ⊢ i 2 = − 1
21 20 oveq1i ⊢ i 2 ⁢ A 2 = -1 ⁢ A 2
22 5 mulm1d ⊢ A ∈ ℂ → -1 ⁢ A 2 = − A 2
23 21 22 eqtrid ⊢ A ∈ ℂ → i 2 ⁢ A 2 = − A 2
24 19 23 eqtrd ⊢ A ∈ ℂ → i ⁢ A 2 = − A 2
25 df-neg ⊢ − A 2 = 0 − A 2
26 24 25 eqtrdi ⊢ A ∈ ℂ → i ⁢ A 2 = 0 − A 2
27 sqneg ⊢ 1 − A 2 ∈ ℂ → − 1 − A 2 2 = 1 − A 2 2
28 8 27 syl ⊢ A ∈ ℂ → − 1 − A 2 2 = 1 − A 2 2
29 7 sqsqrtd ⊢ A ∈ ℂ → 1 − A 2 2 = 1 − A 2
30 28 29 eqtrd ⊢ A ∈ ℂ → − 1 − A 2 2 = 1 − A 2
31 17 26 30 3netr4d ⊢ A ∈ ℂ → i ⁢ A 2 ≠ − 1 − A 2 2
32 oveq1 ⊢ i ⁢ A = − 1 − A 2 → i ⁢ A 2 = − 1 − A 2 2
33 32 necon3i ⊢ i ⁢ A 2 ≠ − 1 − A 2 2 → i ⁢ A ≠ − 1 − A 2
34 31 33 syl ⊢ A ∈ ℂ → i ⁢ A ≠ − 1 − A 2
35 3 10 34 subne0d ⊢ A ∈ ℂ → i ⁢ A − − 1 − A 2 ≠ 0
36 9 35 eqnetrrd ⊢ A ∈ ℂ → i ⁢ A + 1 − A 2 ≠ 0