Metamath Proof Explorer


Theorem atan1

Description: The arctangent of 1 is _pi / 4 . (Contributed by Mario Carneiro, 2-Apr-2015)

Ref Expression
Assertion atan1 ⊢ arctan ⁡ 1 = π 4

Proof

Step Hyp Ref Expression
1 tan4thpi ⊢ tan ⁡ π 4 = 1
2 1 fveq2i ⊢ arctan ⁡ tan ⁡ π 4 = arctan ⁡ 1
3 pire ⊢ π ∈ ℝ
4 4nn ⊢ 4 ∈ ℕ
5 nndivre ⊢ π ∈ ℝ ∧ 4 ∈ ℕ → π 4 ∈ ℝ
6 3 4 5 mp2an ⊢ π 4 ∈ ℝ
7 6 recni ⊢ π 4 ∈ ℂ
8 rere ⊢ π 4 ∈ ℝ → ℜ ⁡ π 4 = π 4
9 6 8 ax-mp ⊢ ℜ ⁡ π 4 = π 4
10 pirp ⊢ π ∈ ℝ +
11 rphalfcl ⊢ π ∈ ℝ + → π 2 ∈ ℝ +
12 10 11 ax-mp ⊢ π 2 ∈ ℝ +
13 rpgt0 ⊢ π 2 ∈ ℝ + → 0 < π 2
14 12 13 ax-mp ⊢ 0 < π 2
15 halfpire ⊢ π 2 ∈ ℝ
16 lt0neg2 ⊢ π 2 ∈ ℝ → 0 < π 2 ↔ − π 2 < 0
17 15 16 ax-mp ⊢ 0 < π 2 ↔ − π 2 < 0
18 14 17 mpbi ⊢ − π 2 < 0
19 nnrp ⊢ 4 ∈ ℕ → 4 ∈ ℝ +
20 4 19 ax-mp ⊢ 4 ∈ ℝ +
21 rpdivcl ⊢ π ∈ ℝ + ∧ 4 ∈ ℝ + → π 4 ∈ ℝ +
22 10 20 21 mp2an ⊢ π 4 ∈ ℝ +
23 rpgt0 ⊢ π 4 ∈ ℝ + → 0 < π 4
24 22 23 ax-mp ⊢ 0 < π 4
25 neghalfpire ⊢ − π 2 ∈ ℝ
26 0re ⊢ 0 ∈ ℝ
27 25 26 6 lttri ⊢ − π 2 < 0 ∧ 0 < π 4 → − π 2 < π 4
28 18 24 27 mp2an ⊢ − π 2 < π 4
29 3 recni ⊢ π ∈ ℂ
30 2cnne0 ⊢ 2 ∈ ℂ ∧ 2 ≠ 0
31 divdiv1 ⊢ π ∈ ℂ ∧ 2 ∈ ℂ ∧ 2 ≠ 0 ∧ 2 ∈ ℂ ∧ 2 ≠ 0 → π 2 2 = π 2 ⋅ 2
32 29 30 30 31 mp3an ⊢ π 2 2 = π 2 ⋅ 2
33 2t2e4 ⊢ 2 ⋅ 2 = 4
34 33 oveq2i ⊢ π 2 ⋅ 2 = π 4
35 32 34 eqtri ⊢ π 2 2 = π 4
36 rphalflt ⊢ π 2 ∈ ℝ + → π 2 2 < π 2
37 12 36 ax-mp ⊢ π 2 2 < π 2
38 35 37 eqbrtrri ⊢ π 4 < π 2
39 25 rexri ⊢ − π 2 ∈ ℝ *
40 15 rexri ⊢ π 2 ∈ ℝ *
41 elioo2 ⊢ − π 2 ∈ ℝ * ∧ π 2 ∈ ℝ * → π 4 ∈ − π 2 π 2 ↔ π 4 ∈ ℝ ∧ − π 2 < π 4 ∧ π 4 < π 2
42 39 40 41 mp2an ⊢ π 4 ∈ − π 2 π 2 ↔ π 4 ∈ ℝ ∧ − π 2 < π 4 ∧ π 4 < π 2
43 6 28 38 42 mpbir3an ⊢ π 4 ∈ − π 2 π 2
44 9 43 eqeltri ⊢ ℜ ⁡ π 4 ∈ − π 2 π 2
45 atantan ⊢ π 4 ∈ ℂ ∧ ℜ ⁡ π 4 ∈ − π 2 π 2 → arctan ⁡ tan ⁡ π 4 = π 4
46 7 44 45 mp2an ⊢ arctan ⁡ tan ⁡ π 4 = π 4
47 2 46 eqtr3i ⊢ arctan ⁡ 1 = π 4