Metamath Proof Explorer


Theorem atcmp

Description: If two atoms are comparable, they are equal. ( atsseq analog.) (Contributed by NM, 13-Oct-2011)

Ref Expression
Hypotheses atcmp.l ⊢ ≤ ˙ = ≤ K
atcmp.a ⊢ A = Atoms ⁡ K
Assertion atcmp ⊢ K ∈ AtLat ∧ P ∈ A ∧ Q ∈ A → P ≤ ˙ Q ↔ P = Q

Proof

Step Hyp Ref Expression
1 atcmp.l ⊢ ≤ ˙ = ≤ K
2 atcmp.a ⊢ A = Atoms ⁡ K
3 atlpos ⊢ K ∈ AtLat → K ∈ Poset
4 3 3ad2ant1 ⊢ K ∈ AtLat ∧ P ∈ A ∧ Q ∈ A → K ∈ Poset
5 eqid ⊢ Base K = Base K
6 5 2 atbase ⊢ P ∈ A → P ∈ Base K
7 6 3ad2ant2 ⊢ K ∈ AtLat ∧ P ∈ A ∧ Q ∈ A → P ∈ Base K
8 5 2 atbase ⊢ Q ∈ A → Q ∈ Base K
9 8 3ad2ant3 ⊢ K ∈ AtLat ∧ P ∈ A ∧ Q ∈ A → Q ∈ Base K
10 eqid ⊢ 0. ⁡ K = 0. ⁡ K
11 5 10 atl0cl ⊢ K ∈ AtLat → 0. ⁡ K ∈ Base K
12 11 3ad2ant1 ⊢ K ∈ AtLat ∧ P ∈ A ∧ Q ∈ A → 0. ⁡ K ∈ Base K
13 eqid ⊢ ⋖ K = ⋖ K
14 10 13 2 atcvr0 ⊢ K ∈ AtLat ∧ P ∈ A → 0. ⁡ K ⋖ K P
15 14 3adant3 ⊢ K ∈ AtLat ∧ P ∈ A ∧ Q ∈ A → 0. ⁡ K ⋖ K P
16 10 13 2 atcvr0 ⊢ K ∈ AtLat ∧ Q ∈ A → 0. ⁡ K ⋖ K Q
17 16 3adant2 ⊢ K ∈ AtLat ∧ P ∈ A ∧ Q ∈ A → 0. ⁡ K ⋖ K Q
18 5 1 13 cvrcmp ⊢ K ∈ Poset ∧ P ∈ Base K ∧ Q ∈ Base K ∧ 0. ⁡ K ∈ Base K ∧ 0. ⁡ K ⋖ K P ∧ 0. ⁡ K ⋖ K Q → P ≤ ˙ Q ↔ P = Q
19 4 7 9 12 15 17 18 syl132anc ⊢ K ∈ AtLat ∧ P ∈ A ∧ Q ∈ A → P ≤ ˙ Q ↔ P = Q