Metamath Proof Explorer


Theorem atcvrj2b

Description: Condition for an atom to be covered by the join of two others. (Contributed by NM, 7-Feb-2012)

Ref Expression
Hypotheses atcvrj1x.l ⊢ ≤ ˙ = ≤ K
atcvrj1x.j ⊢ ∨ ˙ = join ⁡ K
atcvrj1x.c ⊢ C = ⋖ K
atcvrj1x.a ⊢ A = Atoms ⁡ K
Assertion atcvrj2b ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A → Q ≠ R ∧ P ≤ ˙ Q ∨ ˙ R ↔ P C Q ∨ ˙ R

Proof

Step Hyp Ref Expression
1 atcvrj1x.l ⊢ ≤ ˙ = ≤ K
2 atcvrj1x.j ⊢ ∨ ˙ = join ⁡ K
3 atcvrj1x.c ⊢ C = ⋖ K
4 atcvrj1x.a ⊢ A = Atoms ⁡ K
5 simpl3l ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ≤ ˙ Q ∨ ˙ R ∧ P = R → Q ≠ R
6 5 necomd ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ≤ ˙ Q ∨ ˙ R ∧ P = R → R ≠ Q
7 simpl1 ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ≤ ˙ Q ∨ ˙ R ∧ P = R → K ∈ HL
8 simpl23 ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ≤ ˙ Q ∨ ˙ R ∧ P = R → R ∈ A
9 simpl22 ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ≤ ˙ Q ∨ ˙ R ∧ P = R → Q ∈ A
10 2 3 4 atcvr2 ⊢ K ∈ HL ∧ R ∈ A ∧ Q ∈ A → R ≠ Q ↔ R C Q ∨ ˙ R
11 7 8 9 10 syl3anc ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ≤ ˙ Q ∨ ˙ R ∧ P = R → R ≠ Q ↔ R C Q ∨ ˙ R
12 6 11 mpbid ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ≤ ˙ Q ∨ ˙ R ∧ P = R → R C Q ∨ ˙ R
13 breq1 ⊢ P = R → P C Q ∨ ˙ R ↔ R C Q ∨ ˙ R
14 13 adantl ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ≤ ˙ Q ∨ ˙ R ∧ P = R → P C Q ∨ ˙ R ↔ R C Q ∨ ˙ R
15 12 14 mpbird ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ≤ ˙ Q ∨ ˙ R ∧ P = R → P C Q ∨ ˙ R
16 simpl1 ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ≤ ˙ Q ∨ ˙ R ∧ P ≠ R → K ∈ HL
17 simpl2 ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ≤ ˙ Q ∨ ˙ R ∧ P ≠ R → P ∈ A ∧ Q ∈ A ∧ R ∈ A
18 simpr ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ≤ ˙ Q ∨ ˙ R ∧ P ≠ R → P ≠ R
19 simpl3r ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ≤ ˙ Q ∨ ˙ R ∧ P ≠ R → P ≤ ˙ Q ∨ ˙ R
20 1 2 3 4 atcvrj1 ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ P ≠ R ∧ P ≤ ˙ Q ∨ ˙ R → P C Q ∨ ˙ R
21 16 17 18 19 20 syl112anc ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ≤ ˙ Q ∨ ˙ R ∧ P ≠ R → P C Q ∨ ˙ R
22 15 21 pm2.61dane ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ≤ ˙ Q ∨ ˙ R → P C Q ∨ ˙ R
23 22 3expia ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A → Q ≠ R ∧ P ≤ ˙ Q ∨ ˙ R → P C Q ∨ ˙ R
24 hlatl ⊢ K ∈ HL → K ∈ AtLat
25 24 ad2antrr ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ P C Q ∨ ˙ R → K ∈ AtLat
26 simplr1 ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ P C Q ∨ ˙ R → P ∈ A
27 eqid ⊢ 0. ⁡ K = 0. ⁡ K
28 27 4 atn0 ⊢ K ∈ AtLat ∧ P ∈ A → P ≠ 0. ⁡ K
29 25 26 28 syl2anc ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ P C Q ∨ ˙ R → P ≠ 0. ⁡ K
30 simpll ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ P C Q ∨ ˙ R → K ∈ HL
31 eqid ⊢ Base K = Base K
32 31 4 atbase ⊢ P ∈ A → P ∈ Base K
33 26 32 syl ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ P C Q ∨ ˙ R → P ∈ Base K
34 simplr2 ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ P C Q ∨ ˙ R → Q ∈ A
35 simplr3 ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ P C Q ∨ ˙ R → R ∈ A
36 simpr ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ P C Q ∨ ˙ R → P C Q ∨ ˙ R
37 31 2 27 3 4 atcvrj0 ⊢ K ∈ HL ∧ P ∈ Base K ∧ Q ∈ A ∧ R ∈ A ∧ P C Q ∨ ˙ R → P = 0. ⁡ K ↔ Q = R
38 30 33 34 35 36 37 syl131anc ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ P C Q ∨ ˙ R → P = 0. ⁡ K ↔ Q = R
39 38 necon3bid ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ P C Q ∨ ˙ R → P ≠ 0. ⁡ K ↔ Q ≠ R
40 29 39 mpbid ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ P C Q ∨ ˙ R → Q ≠ R
41 hllat ⊢ K ∈ HL → K ∈ Lat
42 41 ad2antrr ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ P C Q ∨ ˙ R → K ∈ Lat
43 31 4 atbase ⊢ Q ∈ A → Q ∈ Base K
44 34 43 syl ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ P C Q ∨ ˙ R → Q ∈ Base K
45 31 4 atbase ⊢ R ∈ A → R ∈ Base K
46 35 45 syl ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ P C Q ∨ ˙ R → R ∈ Base K
47 31 2 latjcl ⊢ K ∈ Lat ∧ Q ∈ Base K ∧ R ∈ Base K → Q ∨ ˙ R ∈ Base K
48 42 44 46 47 syl3anc ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ P C Q ∨ ˙ R → Q ∨ ˙ R ∈ Base K
49 30 33 48 3jca ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ P C Q ∨ ˙ R → K ∈ HL ∧ P ∈ Base K ∧ Q ∨ ˙ R ∈ Base K
50 31 1 3 cvrle ⊢ K ∈ HL ∧ P ∈ Base K ∧ Q ∨ ˙ R ∈ Base K ∧ P C Q ∨ ˙ R → P ≤ ˙ Q ∨ ˙ R
51 49 50 sylancom ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ P C Q ∨ ˙ R → P ≤ ˙ Q ∨ ˙ R
52 40 51 jca ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ P C Q ∨ ˙ R → Q ≠ R ∧ P ≤ ˙ Q ∨ ˙ R
53 52 ex ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A → P C Q ∨ ˙ R → Q ≠ R ∧ P ≤ ˙ Q ∨ ˙ R
54 23 53 impbid ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A → Q ≠ R ∧ P ≤ ˙ Q ∨ ˙ R ↔ P C Q ∨ ˙ R