Metamath Proof Explorer


Theorem atcvrlln2

Description: An atom under a line is covered by it. (Contributed by NM, 2-Jul-2012)

Ref Expression
Hypotheses atcvrlln2.l ⊢ ≤ ˙ = ≤ K
atcvrlln2.c ⊢ C = ⋖ K
atcvrlln2.a ⊢ A = Atoms ⁡ K
atcvrlln2.n ⊢ N = LLines ⁡ K
Assertion atcvrlln2 ⊢ K ∈ HL ∧ P ∈ A ∧ X ∈ N ∧ P ≤ ˙ X → P C X

Proof

Step Hyp Ref Expression
1 atcvrlln2.l ⊢ ≤ ˙ = ≤ K
2 atcvrlln2.c ⊢ C = ⋖ K
3 atcvrlln2.a ⊢ A = Atoms ⁡ K
4 atcvrlln2.n ⊢ N = LLines ⁡ K
5 simpl3 ⊢ K ∈ HL ∧ P ∈ A ∧ X ∈ N ∧ P ≤ ˙ X → X ∈ N
6 simpl1 ⊢ K ∈ HL ∧ P ∈ A ∧ X ∈ N ∧ P ≤ ˙ X → K ∈ HL
7 eqid ⊢ Base K = Base K
8 7 4 llnbase ⊢ X ∈ N → X ∈ Base K
9 5 8 syl ⊢ K ∈ HL ∧ P ∈ A ∧ X ∈ N ∧ P ≤ ˙ X → X ∈ Base K
10 eqid ⊢ join ⁡ K = join ⁡ K
11 7 10 3 4 islln3 ⊢ K ∈ HL ∧ X ∈ Base K → X ∈ N ↔ ∃ q ∈ A ∃ r ∈ A q ≠ r ∧ X = q join ⁡ K r
12 6 9 11 syl2anc ⊢ K ∈ HL ∧ P ∈ A ∧ X ∈ N ∧ P ≤ ˙ X → X ∈ N ↔ ∃ q ∈ A ∃ r ∈ A q ≠ r ∧ X = q join ⁡ K r
13 5 12 mpbid ⊢ K ∈ HL ∧ P ∈ A ∧ X ∈ N ∧ P ≤ ˙ X → ∃ q ∈ A ∃ r ∈ A q ≠ r ∧ X = q join ⁡ K r
14 simp1l1 ⊢ K ∈ HL ∧ P ∈ A ∧ X ∈ N ∧ P ≤ ˙ X ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r ∧ X = q join ⁡ K r → K ∈ HL
15 simp1l2 ⊢ K ∈ HL ∧ P ∈ A ∧ X ∈ N ∧ P ≤ ˙ X ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r ∧ X = q join ⁡ K r → P ∈ A
16 simp2l ⊢ K ∈ HL ∧ P ∈ A ∧ X ∈ N ∧ P ≤ ˙ X ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r ∧ X = q join ⁡ K r → q ∈ A
17 simp2r ⊢ K ∈ HL ∧ P ∈ A ∧ X ∈ N ∧ P ≤ ˙ X ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r ∧ X = q join ⁡ K r → r ∈ A
18 simp3l ⊢ K ∈ HL ∧ P ∈ A ∧ X ∈ N ∧ P ≤ ˙ X ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r ∧ X = q join ⁡ K r → q ≠ r
19 simp1r ⊢ K ∈ HL ∧ P ∈ A ∧ X ∈ N ∧ P ≤ ˙ X ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r ∧ X = q join ⁡ K r → P ≤ ˙ X
20 simp3r ⊢ K ∈ HL ∧ P ∈ A ∧ X ∈ N ∧ P ≤ ˙ X ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r ∧ X = q join ⁡ K r → X = q join ⁡ K r
21 19 20 breqtrd ⊢ K ∈ HL ∧ P ∈ A ∧ X ∈ N ∧ P ≤ ˙ X ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r ∧ X = q join ⁡ K r → P ≤ ˙ q join ⁡ K r
22 1 10 2 3 atcvrj2 ⊢ K ∈ HL ∧ P ∈ A ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r ∧ P ≤ ˙ q join ⁡ K r → P C q join ⁡ K r
23 14 15 16 17 18 21 22 syl132anc ⊢ K ∈ HL ∧ P ∈ A ∧ X ∈ N ∧ P ≤ ˙ X ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r ∧ X = q join ⁡ K r → P C q join ⁡ K r
24 23 20 breqtrrd ⊢ K ∈ HL ∧ P ∈ A ∧ X ∈ N ∧ P ≤ ˙ X ∧ q ∈ A ∧ r ∈ A ∧ q ≠ r ∧ X = q join ⁡ K r → P C X
25 24 3exp ⊢ K ∈ HL ∧ P ∈ A ∧ X ∈ N ∧ P ≤ ˙ X → q ∈ A ∧ r ∈ A → q ≠ r ∧ X = q join ⁡ K r → P C X
26 25 rexlimdvv ⊢ K ∈ HL ∧ P ∈ A ∧ X ∈ N ∧ P ≤ ˙ X → ∃ q ∈ A ∃ r ∈ A q ≠ r ∧ X = q join ⁡ K r → P C X
27 13 26 mpd ⊢ K ∈ HL ∧ P ∈ A ∧ X ∈ N ∧ P ≤ ˙ X → P C X