Metamath Proof Explorer


Axiom ax-hvmul0

Description: Scalar multiplication by zero. We can derive the existence of the negative of a vector from this axiom (see hvsubid and hvsubval ). (Contributed by NM, 29-May-1999) (New usage is discouraged.)

Ref Expression
Assertion ax-hvmul0 A 0 A = 0

Detailed syntax breakdown

Step Hyp Ref Expression
0 cA class A
1 chba class
2 0 1 wcel wff A
3 cc0 class 0
4 csm class
5 3 0 4 co class 0 A
6 c0v class 0
7 5 6 wceq wff 0 A = 0
8 2 7 wi wff A 0 A = 0