Metamath Proof Explorer


Theorem axtgcont

Description: Axiom of Continuity. Axiom A11 of Schwabhauser p. 13. For more information see axtgcont1 . (Contributed by Thierry Arnoux, 16-Mar-2019)

Ref Expression
Hypotheses axtrkg.p ⊢ P = Base G
axtrkg.d ⊢ - ˙ = dist ⁡ G
axtrkg.i ⊢ I = Itv ⁡ G
axtrkg.g ⊢ φ → G ∈ 𝒢 Tarski
axtgcont.1 ⊢ φ → S ⊆ P
axtgcont.2 ⊢ φ → T ⊆ P
axtgcont.3 ⊢ φ → A ∈ P
axtgcont.4 ⊢ φ ∧ u ∈ S ∧ v ∈ T → u ∈ A I v
Assertion axtgcont ⊢ φ → ∃ b ∈ P ∀ x ∈ S ∀ y ∈ T b ∈ x I y

Proof

Step Hyp Ref Expression
1 axtrkg.p ⊢ P = Base G
2 axtrkg.d ⊢ - ˙ = dist ⁡ G
3 axtrkg.i ⊢ I = Itv ⁡ G
4 axtrkg.g ⊢ φ → G ∈ 𝒢 Tarski
5 axtgcont.1 ⊢ φ → S ⊆ P
6 axtgcont.2 ⊢ φ → T ⊆ P
7 axtgcont.3 ⊢ φ → A ∈ P
8 axtgcont.4 ⊢ φ ∧ u ∈ S ∧ v ∈ T → u ∈ A I v
9 8 3expb ⊢ φ ∧ u ∈ S ∧ v ∈ T → u ∈ A I v
10 9 ralrimivva ⊢ φ → ∀ u ∈ S ∀ v ∈ T u ∈ A I v
11 simplr ⊢ a = A ∧ x = u ∧ y = v → x = u
12 simpll ⊢ a = A ∧ x = u ∧ y = v → a = A
13 simpr ⊢ a = A ∧ x = u ∧ y = v → y = v
14 12 13 oveq12d ⊢ a = A ∧ x = u ∧ y = v → a I y = A I v
15 11 14 eleq12d ⊢ a = A ∧ x = u ∧ y = v → x ∈ a I y ↔ u ∈ A I v
16 15 cbvraldva ⊢ a = A ∧ x = u → ∀ y ∈ T x ∈ a I y ↔ ∀ v ∈ T u ∈ A I v
17 16 cbvraldva ⊢ a = A → ∀ x ∈ S ∀ y ∈ T x ∈ a I y ↔ ∀ u ∈ S ∀ v ∈ T u ∈ A I v
18 17 rspcev ⊢ A ∈ P ∧ ∀ u ∈ S ∀ v ∈ T u ∈ A I v → ∃ a ∈ P ∀ x ∈ S ∀ y ∈ T x ∈ a I y
19 7 10 18 syl2anc ⊢ φ → ∃ a ∈ P ∀ x ∈ S ∀ y ∈ T x ∈ a I y
20 1 2 3 4 5 6 axtgcont1 ⊢ φ → ∃ a ∈ P ∀ x ∈ S ∀ y ∈ T x ∈ a I y → ∃ b ∈ P ∀ x ∈ S ∀ y ∈ T b ∈ x I y
21 19 20 mpd ⊢ φ → ∃ b ∈ P ∀ x ∈ S ∀ y ∈ T b ∈ x I y