Metamath Proof Explorer


Theorem basellem8

Description: Lemma for basel . The function F of partial sums of the inverse squares is bounded below by J and above by K , obtained by summing the inequality cot ^ 2 x <_ 1 / x ^ 2 <_ csc ^ 2 x = cot ^ 2 x + 1 over the M roots of the polynomial P , and applying the identity basellem5 . (Contributed by Mario Carneiro, 29-Jul-2014)

Ref Expression
Hypotheses basel.g G = n 1 2 n + 1
basel.f F = seq 1 + n n 2
basel.h H = × π 2 6 × f × 1 f G
basel.j J = H × f × 1 + f × 2 × f G
basel.k K = H × f × 1 + f G
basellem8.n N = 2 M + 1
Assertion basellem8 M J M F M F M K M

Proof

Step Hyp Ref Expression
1 basel.g G = n 1 2 n + 1
2 basel.f F = seq 1 + n n 2
3 basel.h H = × π 2 6 × f × 1 f G
4 basel.j J = H × f × 1 + f × 2 × f G
5 basel.k K = H × f × 1 + f G
6 basellem8.n N = 2 M + 1
7 fzfid M 1 M Fin
8 pire π
9 2nn 2
10 nnmulcl 2 M 2 M
11 9 10 mpan M 2 M
12 11 peano2nnd M 2 M + 1
13 6 12 eqeltrid M N
14 nndivre π N π N
15 8 13 14 sylancr M π N
16 15 resqcld M π N 2
17 16 adantr M k 1 M π N 2
18 6 basellem1 M k 1 M k π N 0 π 2
19 tanrpcl k π N 0 π 2 tan k π N +
20 18 19 syl M k 1 M tan k π N +
21 20 rpred M k 1 M tan k π N
22 20 rpne0d M k 1 M tan k π N 0
23 2z 2
24 znegcl 2 2
25 23 24 ax-mp 2
26 25 a1i M k 1 M 2
27 21 22 26 reexpclzd M k 1 M tan k π N 2
28 17 27 remulcld M k 1 M π N 2 tan k π N 2
29 elfznn k 1 M k
30 29 adantl M k 1 M k
31 30 nnred M k 1 M k
32 30 nnne0d M k 1 M k 0
33 31 32 26 reexpclzd M k 1 M k 2
34 20 rpcnd M k 1 M tan k π N
35 2nn0 2 0
36 expneg tan k π N 2 0 tan k π N 2 = 1 tan k π N 2
37 34 35 36 sylancl M k 1 M tan k π N 2 = 1 tan k π N 2
38 37 oveq2d M k 1 M π N 2 tan k π N 2 = π N 2 1 tan k π N 2
39 15 recnd M π N
40 39 sqcld M π N 2
41 40 adantr M k 1 M π N 2
42 rpexpcl tan k π N + 2 tan k π N 2 +
43 20 23 42 sylancl M k 1 M tan k π N 2 +
44 43 rpcnd M k 1 M tan k π N 2
45 43 rpne0d M k 1 M tan k π N 2 0
46 41 44 45 divrecd M k 1 M π N 2 tan k π N 2 = π N 2 1 tan k π N 2
47 38 46 eqtr4d M k 1 M π N 2 tan k π N 2 = π N 2 tan k π N 2
48 30 nnrpd M k 1 M k +
49 rpexpcl k + 2 k 2 +
50 48 25 49 sylancl M k 1 M k 2 +
51 30 nncnd M k 1 M k
52 51 32 26 expnegd M k 1 M k -2 = 1 k 2
53 2cn 2
54 53 negnegi -2 = 2
55 54 oveq2i k -2 = k 2
56 52 55 eqtr3di M k 1 M 1 k 2 = k 2
57 56 oveq1d M k 1 M 1 k 2 π N 2 = k 2 π N 2
58 nncn k k
59 nnne0 k k 0
60 25 a1i k 2
61 58 59 60 expclzd k k 2
62 30 61 syl M k 1 M k 2
63 51 32 26 expne0d M k 1 M k 2 0
64 41 62 63 divrec2d M k 1 M π N 2 k 2 = 1 k 2 π N 2
65 picn π
66 65 a1i M k 1 M π
67 13 nncnd M N
68 67 adantr M k 1 M N
69 13 nnne0d M N 0
70 69 adantr M k 1 M N 0
71 51 66 68 70 divassd M k 1 M k π N = k π N
72 71 oveq1d M k 1 M k π N 2 = k π N 2
73 39 adantr M k 1 M π N
74 51 73 sqmuld M k 1 M k π N 2 = k 2 π N 2
75 72 74 eqtrd M k 1 M k π N 2 = k 2 π N 2
76 57 64 75 3eqtr4d M k 1 M π N 2 k 2 = k π N 2
77 elioore k π N 0 π 2 k π N
78 18 77 syl M k 1 M k π N
79 78 resqcld M k 1 M k π N 2
80 43 rpred M k 1 M tan k π N 2
81 tangtx k π N 0 π 2 k π N < tan k π N
82 18 81 syl M k 1 M k π N < tan k π N
83 eliooord k π N 0 π 2 0 < k π N k π N < π 2
84 18 83 syl M k 1 M 0 < k π N k π N < π 2
85 84 simpld M k 1 M 0 < k π N
86 78 85 elrpd M k 1 M k π N +
87 86 rpge0d M k 1 M 0 k π N
88 20 rpge0d M k 1 M 0 tan k π N
89 78 21 87 88 lt2sqd M k 1 M k π N < tan k π N k π N 2 < tan k π N 2
90 82 89 mpbid M k 1 M k π N 2 < tan k π N 2
91 79 80 90 ltled M k 1 M k π N 2 tan k π N 2
92 76 91 eqbrtrd M k 1 M π N 2 k 2 tan k π N 2
93 17 50 43 92 lediv23d M k 1 M π N 2 tan k π N 2 k 2
94 47 93 eqbrtrd M k 1 M π N 2 tan k π N 2 k 2
95 7 28 33 94 fsumle M k = 1 M π N 2 tan k π N 2 k = 1 M k 2
96 oveq2 n = M 2 n = 2 M
97 96 oveq1d n = M 2 n + 1 = 2 M + 1
98 97 6 eqtr4di n = M 2 n + 1 = N
99 98 oveq2d n = M 1 2 n + 1 = 1 N
100 99 oveq2d n = M 1 1 2 n + 1 = 1 1 N
101 100 oveq2d n = M π 2 6 1 1 2 n + 1 = π 2 6 1 1 N
102 99 oveq2d n = M -2 1 2 n + 1 = -2 1 N
103 102 oveq2d n = M 1 + -2 1 2 n + 1 = 1 + -2 1 N
104 101 103 oveq12d n = M π 2 6 1 1 2 n + 1 1 + -2 1 2 n + 1 = π 2 6 1 1 N 1 + -2 1 N
105 nnex V
106 105 a1i V
107 ovexd n π 2 6 1 1 2 n + 1 V
108 ovexd n 1 + -2 1 2 n + 1 V
109 8 resqcli π 2
110 6re 6
111 6nn 6
112 111 nnne0i 6 0
113 109 110 112 redivcli π 2 6
114 113 a1i n π 2 6
115 ovexd n 1 1 2 n + 1 V
116 fconstmpt × π 2 6 = n π 2 6
117 116 a1i × π 2 6 = n π 2 6
118 1zzd n 1
119 ovexd n 1 2 n + 1 V
120 fconstmpt × 1 = n 1
121 120 a1i × 1 = n 1
122 1 a1i G = n 1 2 n + 1
123 106 118 119 121 122 offval2 × 1 f G = n 1 1 2 n + 1
124 106 114 115 117 123 offval2 × π 2 6 × f × 1 f G = n π 2 6 1 1 2 n + 1
125 3 124 eqtrid H = n π 2 6 1 1 2 n + 1
126 ovexd n -2 1 2 n + 1 V
127 53 negcli 2
128 127 a1i n 2
129 fconstmpt × 2 = n 2
130 129 a1i × 2 = n 2
131 106 128 119 130 122 offval2 × 2 × f G = n -2 1 2 n + 1
132 106 118 126 121 131 offval2 × 1 + f × 2 × f G = n 1 + -2 1 2 n + 1
133 106 107 108 125 132 offval2 H × f × 1 + f × 2 × f G = n π 2 6 1 1 2 n + 1 1 + -2 1 2 n + 1
134 133 mptru H × f × 1 + f × 2 × f G = n π 2 6 1 1 2 n + 1 1 + -2 1 2 n + 1
135 4 134 eqtri J = n π 2 6 1 1 2 n + 1 1 + -2 1 2 n + 1
136 ovex π 2 6 1 1 N 1 + -2 1 N V
137 104 135 136 fvmpt M J M = π 2 6 1 1 N 1 + -2 1 N
138 113 recni π 2 6
139 138 a1i M π 2 6
140 11 nncnd M 2 M
141 140 67 69 divcld M 2 M N
142 ax-1cn 1
143 subcl 2 M 1 2 M 1
144 140 142 143 sylancl M 2 M 1
145 144 67 69 divcld M 2 M 1 N
146 139 141 145 mulassd M π 2 6 2 M N 2 M 1 N = π 2 6 2 M N 2 M 1 N
147 1cnd M 1
148 67 147 67 69 divsubdird M N 1 N = N N 1 N
149 6 oveq1i N 1 = 2 M + 1 - 1
150 pncan 2 M 1 2 M + 1 - 1 = 2 M
151 140 142 150 sylancl M 2 M + 1 - 1 = 2 M
152 149 151 eqtrid M N 1 = 2 M
153 152 oveq1d M N 1 N = 2 M N
154 67 69 dividd M N N = 1
155 154 oveq1d M N N 1 N = 1 1 N
156 148 153 155 3eqtr3rd M 1 1 N = 2 M N
157 156 oveq2d M π 2 6 1 1 N = π 2 6 2 M N
158 127 a1i M 2
159 67 158 67 69 divdird M N + -2 N = N N + 2 N
160 negsub N 2 N + -2 = N 2
161 67 53 160 sylancl M N + -2 = N 2
162 df-2 2 = 1 + 1
163 6 162 oveq12i N 2 = 2 M + 1 - 1 + 1
164 140 147 147 pnpcan2d M 2 M + 1 - 1 + 1 = 2 M 1
165 163 164 eqtrid M N 2 = 2 M 1
166 161 165 eqtrd M N + -2 = 2 M 1
167 166 oveq1d M N + -2 N = 2 M 1 N
168 158 67 69 divrecd M 2 N = -2 1 N
169 154 168 oveq12d M N N + 2 N = 1 + -2 1 N
170 159 167 169 3eqtr3rd M 1 + -2 1 N = 2 M 1 N
171 157 170 oveq12d M π 2 6 1 1 N 1 + -2 1 N = π 2 6 2 M N 2 M 1 N
172 13 nnsqcld M N 2
173 172 nncnd M N 2
174 6cn 6
175 174 a1i M 6
176 173 175 mulcomd M N 2 6 = 6 N 2
177 176 oveq2d M π 2 2 M 2 M 1 N 2 6 = π 2 2 M 2 M 1 6 N 2
178 109 recni π 2
179 178 a1i M π 2
180 140 144 mulcld M 2 M 2 M 1
181 172 nnne0d M N 2 0
182 173 181 jca M N 2 N 2 0
183 174 112 pm3.2i 6 6 0
184 183 a1i M 6 6 0
185 divmuldiv π 2 2 M 2 M 1 N 2 N 2 0 6 6 0 π 2 N 2 2 M 2 M 1 6 = π 2 2 M 2 M 1 N 2 6
186 179 180 182 184 185 syl22anc M π 2 N 2 2 M 2 M 1 6 = π 2 2 M 2 M 1 N 2 6
187 divmuldiv π 2 2 M 2 M 1 6 6 0 N 2 N 2 0 π 2 6 2 M 2 M 1 N 2 = π 2 2 M 2 M 1 6 N 2
188 179 180 184 182 187 syl22anc M π 2 6 2 M 2 M 1 N 2 = π 2 2 M 2 M 1 6 N 2
189 177 186 188 3eqtr4d M π 2 N 2 2 M 2 M 1 6 = π 2 6 2 M 2 M 1 N 2
190 65 a1i M π
191 190 67 69 sqdivd M π N 2 = π 2 N 2
192 191 oveq1d M π N 2 2 M 2 M 1 6 = π 2 N 2 2 M 2 M 1 6
193 140 67 144 67 69 69 divmuldivd M 2 M N 2 M 1 N = 2 M 2 M 1 N N
194 67 sqvald M N 2 = N N
195 194 oveq2d M 2 M 2 M 1 N 2 = 2 M 2 M 1 N N
196 193 195 eqtr4d M 2 M N 2 M 1 N = 2 M 2 M 1 N 2
197 196 oveq2d M π 2 6 2 M N 2 M 1 N = π 2 6 2 M 2 M 1 N 2
198 189 192 197 3eqtr4d M π N 2 2 M 2 M 1 6 = π 2 6 2 M N 2 M 1 N
199 146 171 198 3eqtr4d M π 2 6 1 1 N 1 + -2 1 N = π N 2 2 M 2 M 1 6
200 eqid x j = 0 M ( N 2 j ) 1 M j x j = x j = 0 M ( N 2 j ) 1 M j x j
201 eqid n 1 M tan n π N 2 = n 1 M tan n π N 2
202 6 200 201 basellem5 M k = 1 M tan k π N 2 = 2 M 2 M 1 6
203 202 oveq2d M π N 2 k = 1 M tan k π N 2 = π N 2 2 M 2 M 1 6
204 199 203 eqtr4d M π 2 6 1 1 N 1 + -2 1 N = π N 2 k = 1 M tan k π N 2
205 27 recnd M k 1 M tan k π N 2
206 7 40 205 fsummulc2 M π N 2 k = 1 M tan k π N 2 = k = 1 M π N 2 tan k π N 2
207 137 204 206 3eqtrd M J M = k = 1 M π N 2 tan k π N 2
208 2 fveq1i F M = seq 1 + n n 2 M
209 oveq1 n = k n 2 = k 2
210 eqid n n 2 = n n 2
211 ovex k 2 V
212 209 210 211 fvmpt k n n 2 k = k 2
213 30 212 syl M k 1 M n n 2 k = k 2
214 id M M
215 nnuz = 1
216 214 215 eleqtrdi M M 1
217 213 216 62 fsumser M k = 1 M k 2 = seq 1 + n n 2 M
218 208 217 eqtr4id M F M = k = 1 M k 2
219 95 207 218 3brtr4d M J M F M
220 78 resincld M k 1 M sin k π N
221 sincosq1sgn k π N 0 π 2 0 < sin k π N 0 < cos k π N
222 18 221 syl M k 1 M 0 < sin k π N 0 < cos k π N
223 222 simpld M k 1 M 0 < sin k π N
224 223 gt0ne0d M k 1 M sin k π N 0
225 220 224 26 reexpclzd M k 1 M sin k π N 2
226 17 225 remulcld M k 1 M π N 2 sin k π N 2
227 sinltx k π N + sin k π N < k π N
228 86 227 syl M k 1 M sin k π N < k π N
229 220 78 228 ltled M k 1 M sin k π N k π N
230 0re 0
231 ltle 0 sin k π N 0 < sin k π N 0 sin k π N
232 230 220 231 sylancr M k 1 M 0 < sin k π N 0 sin k π N
233 223 232 mpd M k 1 M 0 sin k π N
234 220 78 233 87 le2sqd M k 1 M sin k π N k π N sin k π N 2 k π N 2
235 229 234 mpbid M k 1 M sin k π N 2 k π N 2
236 235 76 breqtrrd M k 1 M sin k π N 2 π N 2 k 2
237 220 resqcld M k 1 M sin k π N 2
238 237 17 50 lemuldiv2d M k 1 M k 2 sin k π N 2 π N 2 sin k π N 2 π N 2 k 2
239 220 223 elrpd M k 1 M sin k π N +
240 rpexpcl sin k π N + 2 sin k π N 2 +
241 239 23 240 sylancl M k 1 M sin k π N 2 +
242 33 17 241 lemuldivd M k 1 M k 2 sin k π N 2 π N 2 k 2 π N 2 sin k π N 2
243 238 242 bitr3d M k 1 M sin k π N 2 π N 2 k 2 k 2 π N 2 sin k π N 2
244 236 243 mpbid M k 1 M k 2 π N 2 sin k π N 2
245 220 recnd M k 1 M sin k π N
246 expneg sin k π N 2 0 sin k π N 2 = 1 sin k π N 2
247 245 35 246 sylancl M k 1 M sin k π N 2 = 1 sin k π N 2
248 247 oveq2d M k 1 M π N 2 sin k π N 2 = π N 2 1 sin k π N 2
249 237 recnd M k 1 M sin k π N 2
250 241 rpne0d M k 1 M sin k π N 2 0
251 41 249 250 divrecd M k 1 M π N 2 sin k π N 2 = π N 2 1 sin k π N 2
252 248 251 eqtr4d M k 1 M π N 2 sin k π N 2 = π N 2 sin k π N 2
253 244 252 breqtrrd M k 1 M k 2 π N 2 sin k π N 2
254 7 33 226 253 fsumle M k = 1 M k 2 k = 1 M π N 2 sin k π N 2
255 99 oveq2d n = M 1 + 1 2 n + 1 = 1 + 1 N
256 101 255 oveq12d n = M π 2 6 1 1 2 n + 1 1 + 1 2 n + 1 = π 2 6 1 1 N 1 + 1 N
257 ovexd n 1 + 1 2 n + 1 V
258 106 118 119 121 122 offval2 × 1 + f G = n 1 + 1 2 n + 1
259 106 107 257 125 258 offval2 H × f × 1 + f G = n π 2 6 1 1 2 n + 1 1 + 1 2 n + 1
260 259 mptru H × f × 1 + f G = n π 2 6 1 1 2 n + 1 1 + 1 2 n + 1
261 5 260 eqtri K = n π 2 6 1 1 2 n + 1 1 + 1 2 n + 1
262 ovex π 2 6 1 1 N 1 + 1 N V
263 256 261 262 fvmpt M K M = π 2 6 1 1 N 1 + 1 N
264 peano2cn N N + 1
265 67 264 syl M N + 1
266 265 67 69 divcld M N + 1 N
267 139 141 266 mulassd M π 2 6 2 M N N + 1 N = π 2 6 2 M N N + 1 N
268 67 147 67 69 divdird M N + 1 N = N N + 1 N
269 154 oveq1d M N N + 1 N = 1 + 1 N
270 268 269 eqtr2d M 1 + 1 N = N + 1 N
271 157 270 oveq12d M π 2 6 1 1 N 1 + 1 N = π 2 6 2 M N N + 1 N
272 176 oveq2d M π 2 2 M N + 1 N 2 6 = π 2 2 M N + 1 6 N 2
273 140 265 mulcld M 2 M N + 1
274 divmuldiv π 2 2 M N + 1 N 2 N 2 0 6 6 0 π 2 N 2 2 M N + 1 6 = π 2 2 M N + 1 N 2 6
275 179 273 182 184 274 syl22anc M π 2 N 2 2 M N + 1 6 = π 2 2 M N + 1 N 2 6
276 divmuldiv π 2 2 M N + 1 6 6 0 N 2 N 2 0 π 2 6 2 M N + 1 N 2 = π 2 2 M N + 1 6 N 2
277 179 273 184 182 276 syl22anc M π 2 6 2 M N + 1 N 2 = π 2 2 M N + 1 6 N 2
278 272 275 277 3eqtr4d M π 2 N 2 2 M N + 1 6 = π 2 6 2 M N + 1 N 2
279 78 recoscld M k 1 M cos k π N
280 279 recnd M k 1 M cos k π N
281 280 sqcld M k 1 M cos k π N 2
282 249 281 249 250 divdird M k 1 M sin k π N 2 + cos k π N 2 sin k π N 2 = sin k π N 2 sin k π N 2 + cos k π N 2 sin k π N 2
283 78 recnd M k 1 M k π N
284 sincossq k π N sin k π N 2 + cos k π N 2 = 1
285 283 284 syl M k 1 M sin k π N 2 + cos k π N 2 = 1
286 285 oveq1d M k 1 M sin k π N 2 + cos k π N 2 sin k π N 2 = 1 sin k π N 2
287 249 250 dividd M k 1 M sin k π N 2 sin k π N 2 = 1
288 222 simprd M k 1 M 0 < cos k π N
289 288 gt0ne0d M k 1 M cos k π N 0
290 tanval k π N cos k π N 0 tan k π N = sin k π N cos k π N
291 283 289 290 syl2anc M k 1 M tan k π N = sin k π N cos k π N
292 291 oveq1d M k 1 M tan k π N 2 = sin k π N cos k π N 2
293 245 280 289 sqdivd M k 1 M sin k π N cos k π N 2 = sin k π N 2 cos k π N 2
294 292 293 eqtrd M k 1 M tan k π N 2 = sin k π N 2 cos k π N 2
295 294 oveq2d M k 1 M 1 tan k π N 2 = 1 sin k π N 2 cos k π N 2
296 sqne0 cos k π N cos k π N 2 0 cos k π N 0
297 280 296 syl M k 1 M cos k π N 2 0 cos k π N 0
298 289 297 mpbird M k 1 M cos k π N 2 0
299 249 281 250 298 recdivd M k 1 M 1 sin k π N 2 cos k π N 2 = cos k π N 2 sin k π N 2
300 37 295 299 3eqtrrd M k 1 M cos k π N 2 sin k π N 2 = tan k π N 2
301 287 300 oveq12d M k 1 M sin k π N 2 sin k π N 2 + cos k π N 2 sin k π N 2 = 1 + tan k π N 2
302 282 286 301 3eqtr3d M k 1 M 1 sin k π N 2 = 1 + tan k π N 2
303 addcom 1 tan k π N 2 1 + tan k π N 2 = tan k π N 2 + 1
304 142 205 303 sylancr M k 1 M 1 + tan k π N 2 = tan k π N 2 + 1
305 247 302 304 3eqtrd M k 1 M sin k π N 2 = tan k π N 2 + 1
306 305 sumeq2dv M k = 1 M sin k π N 2 = k = 1 M tan k π N 2 + 1
307 1cnd M k 1 M 1
308 7 205 307 fsumadd M k = 1 M tan k π N 2 + 1 = k = 1 M tan k π N 2 + k = 1 M 1
309 fsumconst 1 M Fin 1 k = 1 M 1 = 1 M 1
310 7 142 309 sylancl M k = 1 M 1 = 1 M 1
311 nnnn0 M M 0
312 hashfz1 M 0 1 M = M
313 311 312 syl M 1 M = M
314 313 oveq1d M 1 M 1 = M 1
315 nncn M M
316 315 mulridd M M 1 = M
317 310 314 316 3eqtrd M k = 1 M 1 = M
318 202 317 oveq12d M k = 1 M tan k π N 2 + k = 1 M 1 = 2 M 2 M 1 6 + M
319 306 308 318 3eqtrd M k = 1 M sin k π N 2 = 2 M 2 M 1 6 + M
320 3cn 3
321 320 a1i M 3
322 140 144 321 adddid M 2 M 2 M - 1 + 3 = 2 M 2 M 1 + 2 M 3
323 3m1e2 3 1 = 2
324 323 162 eqtri 3 1 = 1 + 1
325 324 oveq2i 2 M + 3 - 1 = 2 M + 1 + 1
326 140 147 321 subadd23d M 2 M - 1 + 3 = 2 M + 3 - 1
327 140 147 147 addassd M 2 M + 1 + 1 = 2 M + 1 + 1
328 325 326 327 3eqtr4a M 2 M - 1 + 3 = 2 M + 1 + 1
329 6 oveq1i N + 1 = 2 M + 1 + 1
330 328 329 eqtr4di M 2 M - 1 + 3 = N + 1
331 330 oveq2d M 2 M 2 M - 1 + 3 = 2 M N + 1
332 2cnd M 2
333 332 315 321 mul32d M 2 M 3 = 2 3 M
334 2t3e6 2 3 = 6
335 334 oveq1i 2 3 M = 6 M
336 333 335 eqtrdi M 2 M 3 = 6 M
337 336 oveq2d M 2 M 2 M 1 + 2 M 3 = 2 M 2 M 1 + 6 M
338 322 331 337 3eqtr3d M 2 M N + 1 = 2 M 2 M 1 + 6 M
339 338 oveq1d M 2 M N + 1 6 = 2 M 2 M 1 + 6 M 6
340 mulcl 6 M 6 M
341 174 315 340 sylancr M 6 M
342 112 a1i M 6 0
343 180 341 175 342 divdird M 2 M 2 M 1 + 6 M 6 = 2 M 2 M 1 6 + 6 M 6
344 315 175 342 divcan3d M 6 M 6 = M
345 344 oveq2d M 2 M 2 M 1 6 + 6 M 6 = 2 M 2 M 1 6 + M
346 339 343 345 3eqtrd M 2 M N + 1 6 = 2 M 2 M 1 6 + M
347 319 346 eqtr4d M k = 1 M sin k π N 2 = 2 M N + 1 6
348 191 347 oveq12d M π N 2 k = 1 M sin k π N 2 = π 2 N 2 2 M N + 1 6
349 140 67 265 67 69 69 divmuldivd M 2 M N N + 1 N = 2 M N + 1 N N
350 194 oveq2d M 2 M N + 1 N 2 = 2 M N + 1 N N
351 349 350 eqtr4d M 2 M N N + 1 N = 2 M N + 1 N 2
352 351 oveq2d M π 2 6 2 M N N + 1 N = π 2 6 2 M N + 1 N 2
353 278 348 352 3eqtr4d M π N 2 k = 1 M sin k π N 2 = π 2 6 2 M N N + 1 N
354 267 271 353 3eqtr4d M π 2 6 1 1 N 1 + 1 N = π N 2 k = 1 M sin k π N 2
355 225 recnd M k 1 M sin k π N 2
356 7 40 355 fsummulc2 M π N 2 k = 1 M sin k π N 2 = k = 1 M π N 2 sin k π N 2
357 263 354 356 3eqtrd M K M = k = 1 M π N 2 sin k π N 2
358 254 218 357 3brtr4d M F M K M
359 219 358 jca M J M F M F M K M