Metamath Proof Explorer


Theorem bcnp1n

Description: Binomial coefficient: N + 1 choose N . (Contributed by NM, 20-Jun-2005) (Revised by Mario Carneiro, 8-Nov-2013)

Ref Expression
Assertion bcnp1n ⊢ N ∈ ℕ 0 → ( N + 1 N) = N + 1

Proof

Step Hyp Ref Expression
1 peano2nn0 ⊢ N ∈ ℕ 0 → N + 1 ∈ ℕ 0
2 nn0z ⊢ N ∈ ℕ 0 → N ∈ ℤ
3 bccmpl ⊢ N + 1 ∈ ℕ 0 ∧ N ∈ ℤ → ( N + 1 N) = ( N + 1 N + 1 - N )
4 1 2 3 syl2anc ⊢ N ∈ ℕ 0 → ( N + 1 N) = ( N + 1 N + 1 - N )
5 nn0cn ⊢ N ∈ ℕ 0 → N ∈ ℂ
6 ax-1cn ⊢ 1 ∈ ℂ
7 pncan2 ⊢ N ∈ ℂ ∧ 1 ∈ ℂ → N + 1 - N = 1
8 5 6 7 sylancl ⊢ N ∈ ℕ 0 → N + 1 - N = 1
9 8 oveq2d ⊢ N ∈ ℕ 0 → ( N + 1 N + 1 - N ) = ( N + 1 1 )
10 bcn1 ⊢ N + 1 ∈ ℕ 0 → ( N + 1 1 ) = N + 1
11 1 10 syl ⊢ N ∈ ℕ 0 → ( N + 1 1 ) = N + 1
12 4 9 11 3eqtrd ⊢ N ∈ ℕ 0 → ( N + 1 N) = N + 1