Metamath Proof Explorer


Theorem bcxmaslem1

Description: Lemma for bcxmas . (Contributed by Paul Chapman, 18-May-2007)

Ref Expression
Assertion bcxmaslem1 ⊢ A = B → ( N + A A) = ( N + B B)

Proof

Step Hyp Ref Expression
1 oveq2 ⊢ A = B → N + A = N + B
2 id ⊢ A = B → A = B
3 1 2 oveq12d ⊢ A = B → ( N + A A) = ( N + B B)