Metamath Proof Explorer


Theorem bifald

Description: Infer the equivalence to a contradiction from a negation, in deduction form. (Contributed by Giovanni Mascellani, 15-Sep-2017)

Ref Expression
Hypothesis bifald.1 ⊢ φ → ¬ ψ
Assertion bifald ⊢ φ → ψ ↔ ⊥

Proof

Step Hyp Ref Expression
1 bifald.1 ⊢ φ → ¬ ψ
2 id ⊢ ψ → ψ
3 falim ⊢ ⊥ → ψ
4 2 3 pm5.21ni ⊢ ¬ ψ → ψ ↔ ⊥
5 1 4 syl ⊢ φ → ψ ↔ ⊥