Metamath Proof Explorer


Theorem binom2i

Description: The square of a binomial. (Contributed by NM, 11-Aug-1999)

Ref Expression
Hypotheses binom2.1 ⊢ A ∈ ℂ
binom2.2 ⊢ B ∈ ℂ
Assertion binom2i ⊢ A + B 2 = A 2 + 2 ⁢ A ⁢ B + B 2

Proof

Step Hyp Ref Expression
1 binom2.1 ⊢ A ∈ ℂ
2 binom2.2 ⊢ B ∈ ℂ
3 1 2 addcli ⊢ A + B ∈ ℂ
4 3 1 2 adddii ⊢ A + B ⁢ A + B = A + B ⁢ A + A + B ⁢ B
5 1 2 1 adddiri ⊢ A + B ⁢ A = A ⁢ A + B ⁢ A
6 2 1 mulcomi ⊢ B ⁢ A = A ⁢ B
7 6 oveq2i ⊢ A ⁢ A + B ⁢ A = A ⁢ A + A ⁢ B
8 5 7 eqtri ⊢ A + B ⁢ A = A ⁢ A + A ⁢ B
9 1 2 2 adddiri ⊢ A + B ⁢ B = A ⁢ B + B ⁢ B
10 8 9 oveq12i ⊢ A + B ⁢ A + A + B ⁢ B = A ⁢ A + A ⁢ B + A ⁢ B + B ⁢ B
11 1 1 mulcli ⊢ A ⁢ A ∈ ℂ
12 1 2 mulcli ⊢ A ⁢ B ∈ ℂ
13 11 12 addcli ⊢ A ⁢ A + A ⁢ B ∈ ℂ
14 2 2 mulcli ⊢ B ⁢ B ∈ ℂ
15 13 12 14 addassi ⊢ A ⁢ A + A ⁢ B + A ⁢ B + B ⁢ B = A ⁢ A + A ⁢ B + A ⁢ B + B ⁢ B
16 11 12 12 addassi ⊢ A ⁢ A + A ⁢ B + A ⁢ B = A ⁢ A + A ⁢ B + A ⁢ B
17 16 oveq1i ⊢ A ⁢ A + A ⁢ B + A ⁢ B + B ⁢ B = A ⁢ A + A ⁢ B + A ⁢ B + B ⁢ B
18 10 15 17 3eqtr2i ⊢ A + B ⁢ A + A + B ⁢ B = A ⁢ A + A ⁢ B + A ⁢ B + B ⁢ B
19 4 18 eqtri ⊢ A + B ⁢ A + B = A ⁢ A + A ⁢ B + A ⁢ B + B ⁢ B
20 3 sqvali ⊢ A + B 2 = A + B ⁢ A + B
21 1 sqvali ⊢ A 2 = A ⁢ A
22 12 2timesi ⊢ 2 ⁢ A ⁢ B = A ⁢ B + A ⁢ B
23 21 22 oveq12i ⊢ A 2 + 2 ⁢ A ⁢ B = A ⁢ A + A ⁢ B + A ⁢ B
24 2 sqvali ⊢ B 2 = B ⁢ B
25 23 24 oveq12i ⊢ A 2 + 2 ⁢ A ⁢ B + B 2 = A ⁢ A + A ⁢ B + A ⁢ B + B ⁢ B
26 19 20 25 3eqtr4i ⊢ A + B 2 = A 2 + 2 ⁢ A ⁢ B + B 2