Metamath Proof Explorer


Theorem binom2subadd

Description: The difference of the squares of the sum and difference of two complex numbers A and B . (Contributed by Thierry Arnoux, 5-Nov-2025)

Ref Expression
Hypotheses binom2subadd.1 ⊢ φ → A ∈ ℂ
binom2subadd.2 ⊢ φ → B ∈ ℂ
Assertion binom2subadd ⊢ φ → A + B 2 − A − B 2 = 4 ⁢ A ⁢ B

Proof

Step Hyp Ref Expression
1 binom2subadd.1 ⊢ φ → A ∈ ℂ
2 binom2subadd.2 ⊢ φ → B ∈ ℂ
3 1 2 addcld ⊢ φ → A + B ∈ ℂ
4 1 2 subcld ⊢ φ → A − B ∈ ℂ
5 subsq ⊢ A + B ∈ ℂ ∧ A − B ∈ ℂ → A + B 2 − A − B 2 = A + B + A − B ⁢ A + B - A − B
6 3 4 5 syl2anc ⊢ φ → A + B 2 − A − B 2 = A + B + A − B ⁢ A + B - A − B
7 1 2 1 ppncand ⊢ φ → A + B + A − B = A + A
8 1 2timesd ⊢ φ → 2 ⁢ A = A + A
9 7 8 eqtr4d ⊢ φ → A + B + A − B = 2 ⁢ A
10 1 2 2 pnncand ⊢ φ → A + B - A − B = B + B
11 2 2timesd ⊢ φ → 2 ⁢ B = B + B
12 10 11 eqtr4d ⊢ φ → A + B - A − B = 2 ⁢ B
13 9 12 oveq12d ⊢ φ → A + B + A − B ⁢ A + B - A − B = 2 ⁢ A ⁢ 2 ⁢ B
14 2cnd ⊢ φ → 2 ∈ ℂ
15 14 1 14 2 mul4d ⊢ φ → 2 ⁢ A ⁢ 2 ⁢ B = 2 ⋅ 2 ⁢ A ⁢ B
16 6 13 15 3eqtrd ⊢ φ → A + B 2 − A − B 2 = 2 ⋅ 2 ⁢ A ⁢ B
17 2t2e4 ⊢ 2 ⋅ 2 = 4
18 17 oveq1i ⊢ 2 ⋅ 2 ⁢ A ⁢ B = 4 ⁢ A ⁢ B
19 16 18 eqtrdi ⊢ φ → A + B 2 − A − B 2 = 4 ⁢ A ⁢ B