Metamath Proof Explorer


Theorem bj-abf

Description: Shorter proof of abf (which should be kept as abfALT). (Contributed by BJ, 24-Jul-2019) (Proof modification is discouraged.)

Ref Expression
Hypothesis bj-abf.1 ¬ φ
Assertion bj-abf x | φ =

Proof

Step Hyp Ref Expression
1 bj-abf.1 ¬ φ
2 bj-ab0 x ¬ φ x | φ =
3 2 1 mpg x | φ =