Metamath Proof Explorer


Theorem bj-ax12ssb

Description: Axiom bj-ax12 expressed using substitution. (Contributed by BJ, 26-Dec-2020) (Proof modification is discouraged.)

Ref Expression
Assertion bj-ax12ssb ⊢ t x φ → t x φ

Proof

Step Hyp Ref Expression
1 bj-ax12 ⊢ ∀ x x = t → φ → ∀ x x = t → φ
2 sb6 ⊢ t x φ ↔ ∀ x x = t → φ
3 2 imbi2i ⊢ φ → t x φ ↔ φ → ∀ x x = t → φ
4 3 imbi2i ⊢ x = t → φ → t x φ ↔ x = t → φ → ∀ x x = t → φ
5 4 albii ⊢ ∀ x x = t → φ → t x φ ↔ ∀ x x = t → φ → ∀ x x = t → φ
6 1 5 mpbir ⊢ ∀ x x = t → φ → t x φ
7 sb6 ⊢ t x φ → t x φ ↔ ∀ x x = t → φ → t x φ
8 6 7 mpbir ⊢ t x φ → t x φ