Metamath Proof Explorer


Theorem breq12d

Description: Equality deduction for a binary relation. (Contributed by NM, 8-Feb-1996) (Proof shortened by Andrew Salmon, 9-Jul-2011)

Ref Expression
Hypotheses breq1d.1 ⊢ φ → A = B
breq12d.2 ⊢ φ → C = D
Assertion breq12d ⊢ φ → A R C ↔ B R D

Proof

Step Hyp Ref Expression
1 breq1d.1 ⊢ φ → A = B
2 breq12d.2 ⊢ φ → C = D
3 breq12 ⊢ A = B ∧ C = D → A R C ↔ B R D
4 1 2 3 syl2anc ⊢ φ → A R C ↔ B R D