Metamath Proof Explorer


Theorem carden2a

Description: If two sets have equal nonzero cardinalities, then they are equinumerous. This assertion and carden2b are meant to replace carden in ZF without AC. (Contributed by Mario Carneiro, 9-Jan-2013)

Ref Expression
Assertion carden2a ⊢ card ⁡ A = card ⁡ B ∧ card ⁡ A ≠ ∅ → A ≈ B

Proof

Step Hyp Ref Expression
1 df-ne ⊢ card ⁡ A ≠ ∅ ↔ ¬ card ⁡ A = ∅
2 ndmfv ⊢ ¬ B ∈ dom ⁡ card → card ⁡ B = ∅
3 eqeq1 ⊢ card ⁡ A = card ⁡ B → card ⁡ A = ∅ ↔ card ⁡ B = ∅
4 2 3 imbitrrid ⊢ card ⁡ A = card ⁡ B → ¬ B ∈ dom ⁡ card → card ⁡ A = ∅
5 4 con1d ⊢ card ⁡ A = card ⁡ B → ¬ card ⁡ A = ∅ → B ∈ dom ⁡ card
6 5 imp ⊢ card ⁡ A = card ⁡ B ∧ ¬ card ⁡ A = ∅ → B ∈ dom ⁡ card
7 cardid2 ⊢ B ∈ dom ⁡ card → card ⁡ B ≈ B
8 6 7 syl ⊢ card ⁡ A = card ⁡ B ∧ ¬ card ⁡ A = ∅ → card ⁡ B ≈ B
9 breq2 ⊢ card ⁡ A = card ⁡ B → A ≈ card ⁡ A ↔ A ≈ card ⁡ B
10 entr ⊢ A ≈ card ⁡ B ∧ card ⁡ B ≈ B → A ≈ B
11 10 ex ⊢ A ≈ card ⁡ B → card ⁡ B ≈ B → A ≈ B
12 9 11 biimtrdi ⊢ card ⁡ A = card ⁡ B → A ≈ card ⁡ A → card ⁡ B ≈ B → A ≈ B
13 cardid2 ⊢ A ∈ dom ⁡ card → card ⁡ A ≈ A
14 ndmfv ⊢ ¬ A ∈ dom ⁡ card → card ⁡ A = ∅
15 13 14 nsyl4 ⊢ ¬ card ⁡ A = ∅ → card ⁡ A ≈ A
16 15 ensymd ⊢ ¬ card ⁡ A = ∅ → A ≈ card ⁡ A
17 12 16 impel ⊢ card ⁡ A = card ⁡ B ∧ ¬ card ⁡ A = ∅ → card ⁡ B ≈ B → A ≈ B
18 8 17 mpd ⊢ card ⁡ A = card ⁡ B ∧ ¬ card ⁡ A = ∅ → A ≈ B
19 1 18 sylan2b ⊢ card ⁡ A = card ⁡ B ∧ card ⁡ A ≠ ∅ → A ≈ B