Metamath Proof Explorer


Theorem ccats1alpha

Description: A concatenation of a word with a singleton word is a word over an alphabet S iff the symbols of both words belong to the alphabet S . (Contributed by AV, 27-Mar-2022)

Ref Expression
Assertion ccats1alpha ⊢ A ∈ Word V ∧ X ∈ U → A ++ ⟨“ X ”⟩ ∈ Word S ↔ A ∈ Word S ∧ X ∈ S

Proof

Step Hyp Ref Expression
1 wrdv ⊢ A ∈ Word V → A ∈ Word V
2 s1cli ⊢ ⟨“ X ”⟩ ∈ Word V
3 2 a1i ⊢ X ∈ U → ⟨“ X ”⟩ ∈ Word V
4 ccatalpha ⊢ A ∈ Word V ∧ ⟨“ X ”⟩ ∈ Word V → A ++ ⟨“ X ”⟩ ∈ Word S ↔ A ∈ Word S ∧ ⟨“ X ”⟩ ∈ Word S
5 1 3 4 syl2an ⊢ A ∈ Word V ∧ X ∈ U → A ++ ⟨“ X ”⟩ ∈ Word S ↔ A ∈ Word S ∧ ⟨“ X ”⟩ ∈ Word S
6 simpr ⊢ X ∈ U ∧ ⟨“ X ”⟩ ∈ Word S → ⟨“ X ”⟩ ∈ Word S
7 s1len ⊢ ⟨“ X ”⟩ = 1
8 wrdl1exs1 ⊢ ⟨“ X ”⟩ ∈ Word S ∧ ⟨“ X ”⟩ = 1 → ∃ w ∈ S ⟨“ X ”⟩ = ⟨“ w ”⟩
9 6 7 8 sylancl ⊢ X ∈ U ∧ ⟨“ X ”⟩ ∈ Word S → ∃ w ∈ S ⟨“ X ”⟩ = ⟨“ w ”⟩
10 elex ⊢ X ∈ U → X ∈ V
11 10 adantr ⊢ X ∈ U ∧ ⟨“ X ”⟩ ∈ Word S → X ∈ V
12 elex ⊢ w ∈ S → w ∈ V
13 s111 ⊢ X ∈ V ∧ w ∈ V → ⟨“ X ”⟩ = ⟨“ w ”⟩ ↔ X = w
14 11 12 13 syl2an ⊢ X ∈ U ∧ ⟨“ X ”⟩ ∈ Word S ∧ w ∈ S → ⟨“ X ”⟩ = ⟨“ w ”⟩ ↔ X = w
15 simpr ⊢ X ∈ U ∧ ⟨“ X ”⟩ ∈ Word S ∧ w ∈ S → w ∈ S
16 eleq1 ⊢ X = w → X ∈ S ↔ w ∈ S
17 15 16 syl5ibrcom ⊢ X ∈ U ∧ ⟨“ X ”⟩ ∈ Word S ∧ w ∈ S → X = w → X ∈ S
18 14 17 sylbid ⊢ X ∈ U ∧ ⟨“ X ”⟩ ∈ Word S ∧ w ∈ S → ⟨“ X ”⟩ = ⟨“ w ”⟩ → X ∈ S
19 18 rexlimdva ⊢ X ∈ U ∧ ⟨“ X ”⟩ ∈ Word S → ∃ w ∈ S ⟨“ X ”⟩ = ⟨“ w ”⟩ → X ∈ S
20 9 19 mpd ⊢ X ∈ U ∧ ⟨“ X ”⟩ ∈ Word S → X ∈ S
21 20 ex ⊢ X ∈ U → ⟨“ X ”⟩ ∈ Word S → X ∈ S
22 s1cl ⊢ X ∈ S → ⟨“ X ”⟩ ∈ Word S
23 21 22 impbid1 ⊢ X ∈ U → ⟨“ X ”⟩ ∈ Word S ↔ X ∈ S
24 23 anbi2d ⊢ X ∈ U → A ∈ Word S ∧ ⟨“ X ”⟩ ∈ Word S ↔ A ∈ Word S ∧ X ∈ S
25 24 adantl ⊢ A ∈ Word V ∧ X ∈ U → A ∈ Word S ∧ ⟨“ X ”⟩ ∈ Word S ↔ A ∈ Word S ∧ X ∈ S
26 5 25 bitrd ⊢ A ∈ Word V ∧ X ∈ U → A ++ ⟨“ X ”⟩ ∈ Word S ↔ A ∈ Word S ∧ X ∈ S