Metamath Proof Explorer


Theorem cdleme0ex2N

Description: Part of proof of Lemma E in Crawley p. 113. Note that ( P .\/ u ) = ( Q .\/ u ) is a shorter way to express u =/= P /\ u =/= Q /\ u .<_ ( P .\/ Q ) . (Contributed by NM, 9-Nov-2012) (New usage is discouraged.)

Ref Expression
Hypotheses cdleme0.l ⊢ ≤ ˙ = ≤ K
cdleme0.j ⊢ ∨ ˙ = join ⁡ K
cdleme0.m ⊢ ∧ ˙ = meet ⁡ K
cdleme0.a ⊢ A = Atoms ⁡ K
cdleme0.h ⊢ H = LHyp ⁡ K
cdleme0.u ⊢ U = P ∨ ˙ Q ∧ ˙ W
Assertion cdleme0ex2N ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q → ∃ u ∈ A P ∨ ˙ u = Q ∨ ˙ u ∧ u ≤ ˙ W

Proof

Step Hyp Ref Expression
1 cdleme0.l ⊢ ≤ ˙ = ≤ K
2 cdleme0.j ⊢ ∨ ˙ = join ⁡ K
3 cdleme0.m ⊢ ∧ ˙ = meet ⁡ K
4 cdleme0.a ⊢ A = Atoms ⁡ K
5 cdleme0.h ⊢ H = LHyp ⁡ K
6 cdleme0.u ⊢ U = P ∨ ˙ Q ∧ ˙ W
7 simp1 ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q → K ∈ HL ∧ W ∈ H
8 simp2l ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q → P ∈ A ∧ ¬ P ≤ ˙ W
9 simp2rl ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q → Q ∈ A
10 simp3 ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q → P ≠ Q
11 1 2 3 4 5 6 cdleme0ex1N ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ P ≠ Q → ∃ u ∈ A u ≤ ˙ P ∨ ˙ Q ∧ u ≤ ˙ W
12 7 8 9 10 11 syl121anc ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q → ∃ u ∈ A u ≤ ˙ P ∨ ˙ Q ∧ u ≤ ˙ W
13 simp11l ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q ∧ u ∈ A ∧ u ≤ ˙ W → K ∈ HL
14 hlcvl ⊢ K ∈ HL → K ∈ CvLat
15 13 14 syl ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q ∧ u ∈ A ∧ u ≤ ˙ W → K ∈ CvLat
16 simp2ll ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q → P ∈ A
17 16 3ad2ant1 ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q ∧ u ∈ A ∧ u ≤ ˙ W → P ∈ A
18 9 3ad2ant1 ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q ∧ u ∈ A ∧ u ≤ ˙ W → Q ∈ A
19 simp2 ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q ∧ u ∈ A ∧ u ≤ ˙ W → u ∈ A
20 simp13 ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q ∧ u ∈ A ∧ u ≤ ˙ W → P ≠ Q
21 4 1 2 cvlsupr2 ⊢ K ∈ CvLat ∧ P ∈ A ∧ Q ∈ A ∧ u ∈ A ∧ P ≠ Q → P ∨ ˙ u = Q ∨ ˙ u ↔ u ≠ P ∧ u ≠ Q ∧ u ≤ ˙ P ∨ ˙ Q
22 15 17 18 19 20 21 syl131anc ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q ∧ u ∈ A ∧ u ≤ ˙ W → P ∨ ˙ u = Q ∨ ˙ u ↔ u ≠ P ∧ u ≠ Q ∧ u ≤ ˙ P ∨ ˙ Q
23 df-3an ⊢ u ≠ P ∧ u ≠ Q ∧ u ≤ ˙ P ∨ ˙ Q ↔ u ≠ P ∧ u ≠ Q ∧ u ≤ ˙ P ∨ ˙ Q
24 simp3 ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q ∧ u ∈ A ∧ u ≤ ˙ W → u ≤ ˙ W
25 simp2lr ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q → ¬ P ≤ ˙ W
26 25 3ad2ant1 ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q ∧ u ∈ A ∧ u ≤ ˙ W → ¬ P ≤ ˙ W
27 nbrne2 ⊢ u ≤ ˙ W ∧ ¬ P ≤ ˙ W → u ≠ P
28 24 26 27 syl2anc ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q ∧ u ∈ A ∧ u ≤ ˙ W → u ≠ P
29 simp2rr ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q → ¬ Q ≤ ˙ W
30 29 3ad2ant1 ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q ∧ u ∈ A ∧ u ≤ ˙ W → ¬ Q ≤ ˙ W
31 nbrne2 ⊢ u ≤ ˙ W ∧ ¬ Q ≤ ˙ W → u ≠ Q
32 24 30 31 syl2anc ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q ∧ u ∈ A ∧ u ≤ ˙ W → u ≠ Q
33 28 32 jca ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q ∧ u ∈ A ∧ u ≤ ˙ W → u ≠ P ∧ u ≠ Q
34 33 biantrurd ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q ∧ u ∈ A ∧ u ≤ ˙ W → u ≤ ˙ P ∨ ˙ Q ↔ u ≠ P ∧ u ≠ Q ∧ u ≤ ˙ P ∨ ˙ Q
35 23 34 bitr4id ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q ∧ u ∈ A ∧ u ≤ ˙ W → u ≠ P ∧ u ≠ Q ∧ u ≤ ˙ P ∨ ˙ Q ↔ u ≤ ˙ P ∨ ˙ Q
36 22 35 bitrd ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q ∧ u ∈ A ∧ u ≤ ˙ W → P ∨ ˙ u = Q ∨ ˙ u ↔ u ≤ ˙ P ∨ ˙ Q
37 36 3expia ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q ∧ u ∈ A → u ≤ ˙ W → P ∨ ˙ u = Q ∨ ˙ u ↔ u ≤ ˙ P ∨ ˙ Q
38 37 pm5.32rd ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q ∧ u ∈ A → P ∨ ˙ u = Q ∨ ˙ u ∧ u ≤ ˙ W ↔ u ≤ ˙ P ∨ ˙ Q ∧ u ≤ ˙ W
39 38 rexbidva ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q → ∃ u ∈ A P ∨ ˙ u = Q ∨ ˙ u ∧ u ≤ ˙ W ↔ ∃ u ∈ A u ≤ ˙ P ∨ ˙ Q ∧ u ≤ ˙ W
40 12 39 mpbird ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q → ∃ u ∈ A P ∨ ˙ u = Q ∨ ˙ u ∧ u ≤ ˙ W