Metamath Proof Explorer


Theorem cdlemg43

Description: Part of proof of Lemma G of Crawley p. 116, third line of third paragraph on p. 117. (Contributed by NM, 3-Jun-2013)

Ref Expression
Hypotheses cdlemg42.l ⊢ ≤ ˙ = ≤ K
cdlemg42.j ⊢ ∨ ˙ = join ⁡ K
cdlemg42.a ⊢ A = Atoms ⁡ K
cdlemg42.h ⊢ H = LHyp ⁡ K
cdlemg42.t ⊢ T = LTrn ⁡ K ⁡ W
cdlemg42.r ⊢ R = trL ⁡ K ⁡ W
cdlemg42.m ⊢ ∧ ˙ = meet ⁡ K
Assertion cdlemg43 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ G ⁡ P ≠ P ∧ R ⁡ F ≠ R ⁡ G → F ⁡ G ⁡ P = G ⁡ P ∨ ˙ R ⁡ F ∧ ˙ F ⁡ P ∨ ˙ R ⁡ G

Proof

Step Hyp Ref Expression
1 cdlemg42.l ⊢ ≤ ˙ = ≤ K
2 cdlemg42.j ⊢ ∨ ˙ = join ⁡ K
3 cdlemg42.a ⊢ A = Atoms ⁡ K
4 cdlemg42.h ⊢ H = LHyp ⁡ K
5 cdlemg42.t ⊢ T = LTrn ⁡ K ⁡ W
6 cdlemg42.r ⊢ R = trL ⁡ K ⁡ W
7 cdlemg42.m ⊢ ∧ ˙ = meet ⁡ K
8 simp1 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ G ⁡ P ≠ P ∧ R ⁡ F ≠ R ⁡ G → K ∈ HL ∧ W ∈ H
9 simp2l ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ G ⁡ P ≠ P ∧ R ⁡ F ≠ R ⁡ G → F ∈ T
10 simp31 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ G ⁡ P ≠ P ∧ R ⁡ F ≠ R ⁡ G → P ∈ A ∧ ¬ P ≤ ˙ W
11 simp2r ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ G ⁡ P ≠ P ∧ R ⁡ F ≠ R ⁡ G → G ∈ T
12 1 3 4 5 ltrnel ⊢ K ∈ HL ∧ W ∈ H ∧ G ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W → G ⁡ P ∈ A ∧ ¬ G ⁡ P ≤ ˙ W
13 8 11 10 12 syl3anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ G ⁡ P ≠ P ∧ R ⁡ F ≠ R ⁡ G → G ⁡ P ∈ A ∧ ¬ G ⁡ P ≤ ˙ W
14 1 2 3 4 5 6 cdlemg42 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ G ⁡ P ≠ P ∧ R ⁡ F ≠ R ⁡ G → ¬ G ⁡ P ≤ ˙ P ∨ ˙ F ⁡ P
15 1 2 7 3 4 5 6 cdlemc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ G ⁡ P ∈ A ∧ ¬ G ⁡ P ≤ ˙ W ∧ ¬ G ⁡ P ≤ ˙ P ∨ ˙ F ⁡ P → F ⁡ G ⁡ P = G ⁡ P ∨ ˙ R ⁡ F ∧ ˙ F ⁡ P ∨ ˙ P ∨ ˙ G ⁡ P ∧ ˙ W
16 8 9 10 13 14 15 syl131anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ G ⁡ P ≠ P ∧ R ⁡ F ≠ R ⁡ G → F ⁡ G ⁡ P = G ⁡ P ∨ ˙ R ⁡ F ∧ ˙ F ⁡ P ∨ ˙ P ∨ ˙ G ⁡ P ∧ ˙ W
17 1 2 7 3 4 5 6 trlval2 ⊢ K ∈ HL ∧ W ∈ H ∧ G ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W → R ⁡ G = P ∨ ˙ G ⁡ P ∧ ˙ W
18 8 11 10 17 syl3anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ G ⁡ P ≠ P ∧ R ⁡ F ≠ R ⁡ G → R ⁡ G = P ∨ ˙ G ⁡ P ∧ ˙ W
19 18 oveq2d ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ G ⁡ P ≠ P ∧ R ⁡ F ≠ R ⁡ G → F ⁡ P ∨ ˙ R ⁡ G = F ⁡ P ∨ ˙ P ∨ ˙ G ⁡ P ∧ ˙ W
20 19 oveq2d ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ G ⁡ P ≠ P ∧ R ⁡ F ≠ R ⁡ G → G ⁡ P ∨ ˙ R ⁡ F ∧ ˙ F ⁡ P ∨ ˙ R ⁡ G = G ⁡ P ∨ ˙ R ⁡ F ∧ ˙ F ⁡ P ∨ ˙ P ∨ ˙ G ⁡ P ∧ ˙ W
21 16 20 eqtr4d ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ G ⁡ P ≠ P ∧ R ⁡ F ≠ R ⁡ G → F ⁡ G ⁡ P = G ⁡ P ∨ ˙ R ⁡ F ∧ ˙ F ⁡ P ∨ ˙ R ⁡ G