Metamath Proof Explorer


Theorem ceqsexgv

Description: Elimination of an existential quantifier, using implicit substitution. (Contributed by NM, 29-Dec-1996) Drop ax-10 and ax-12 . (Revised by GG, 1-Dec-2023)

Ref Expression
Hypothesis ceqsexgv.1 ⊢ x = A → φ ↔ ψ
Assertion ceqsexgv ⊢ A ∈ V → ∃ x x = A ∧ φ ↔ ψ

Proof

Step Hyp Ref Expression
1 ceqsexgv.1 ⊢ x = A → φ ↔ ψ
2 id ⊢ x = A → x = A
3 2 1 cgsexg ⊢ A ∈ V → ∃ x x = A ∧ φ ↔ ψ