Metamath Proof Explorer


Theorem cgr3simp1

Description: Deduce segment congruence from a triangle congruence. This is a portion of the theorem that corresponding parts of congruent triangles are congruent (CPCTC), focusing on a specific segment. (Contributed by Thierry Arnoux, 27-Apr-2019)

Ref Expression
Hypotheses tgcgrxfr.p ⊢ P = Base G
tgcgrxfr.m ⊢ - ˙ = dist ⁡ G
tgcgrxfr.i ⊢ I = Itv ⁡ G
tgcgrxfr.r ⊢ ∼ ˙ = ∼ 𝒢 ⁡ G
tgcgrxfr.g ⊢ φ → G ∈ 𝒢 Tarski
tgbtwnxfr.a ⊢ φ → A ∈ P
tgbtwnxfr.b ⊢ φ → B ∈ P
tgbtwnxfr.c ⊢ φ → C ∈ P
tgbtwnxfr.d ⊢ φ → D ∈ P
tgbtwnxfr.e ⊢ φ → E ∈ P
tgbtwnxfr.f ⊢ φ → F ∈ P
tgbtwnxfr.2 ⊢ φ → ⟨“ ABC ”⟩ ∼ ˙ ⟨“ DEF ”⟩
Assertion cgr3simp1 ⊢ φ → A - ˙ B = D - ˙ E

Proof

Step Hyp Ref Expression
1 tgcgrxfr.p ⊢ P = Base G
2 tgcgrxfr.m ⊢ - ˙ = dist ⁡ G
3 tgcgrxfr.i ⊢ I = Itv ⁡ G
4 tgcgrxfr.r ⊢ ∼ ˙ = ∼ 𝒢 ⁡ G
5 tgcgrxfr.g ⊢ φ → G ∈ 𝒢 Tarski
6 tgbtwnxfr.a ⊢ φ → A ∈ P
7 tgbtwnxfr.b ⊢ φ → B ∈ P
8 tgbtwnxfr.c ⊢ φ → C ∈ P
9 tgbtwnxfr.d ⊢ φ → D ∈ P
10 tgbtwnxfr.e ⊢ φ → E ∈ P
11 tgbtwnxfr.f ⊢ φ → F ∈ P
12 tgbtwnxfr.2 ⊢ φ → ⟨“ ABC ”⟩ ∼ ˙ ⟨“ DEF ”⟩
13 1 2 4 5 6 7 8 9 10 11 trgcgrg ⊢ φ → ⟨“ ABC ”⟩ ∼ ˙ ⟨“ DEF ”⟩ ↔ A - ˙ B = D - ˙ E ∧ B - ˙ C = E - ˙ F ∧ C - ˙ A = F - ˙ D
14 12 13 mpbid ⊢ φ → A - ˙ B = D - ˙ E ∧ B - ˙ C = E - ˙ F ∧ C - ˙ A = F - ˙ D
15 14 simp1d ⊢ φ → A - ˙ B = D - ˙ E