Metamath Proof Explorer


Theorem chj12

Description: A rearrangement of Hilbert lattice join. (Contributed by NM, 15-Jun-2006) (New usage is discouraged.)

Ref Expression
Assertion chj12 ⊢ A ∈ C ℋ ∧ B ∈ C ℋ ∧ C ∈ C ℋ → A ∨ ℋ B ∨ ℋ C = B ∨ ℋ A ∨ ℋ C

Proof

Step Hyp Ref Expression
1 chjcom ⊢ A ∈ C ℋ ∧ B ∈ C ℋ → A ∨ ℋ B = B ∨ ℋ A
2 1 3adant3 ⊢ A ∈ C ℋ ∧ B ∈ C ℋ ∧ C ∈ C ℋ → A ∨ ℋ B = B ∨ ℋ A
3 2 oveq1d ⊢ A ∈ C ℋ ∧ B ∈ C ℋ ∧ C ∈ C ℋ → A ∨ ℋ B ∨ ℋ C = B ∨ ℋ A ∨ ℋ C
4 chjass ⊢ A ∈ C ℋ ∧ B ∈ C ℋ ∧ C ∈ C ℋ → A ∨ ℋ B ∨ ℋ C = A ∨ ℋ B ∨ ℋ C
5 chjass ⊢ B ∈ C ℋ ∧ A ∈ C ℋ ∧ C ∈ C ℋ → B ∨ ℋ A ∨ ℋ C = B ∨ ℋ A ∨ ℋ C
6 5 3com12 ⊢ A ∈ C ℋ ∧ B ∈ C ℋ ∧ C ∈ C ℋ → B ∨ ℋ A ∨ ℋ C = B ∨ ℋ A ∨ ℋ C
7 3 4 6 3eqtr3d ⊢ A ∈ C ℋ ∧ B ∈ C ℋ ∧ C ∈ C ℋ → A ∨ ℋ B ∨ ℋ C = B ∨ ℋ A ∨ ℋ C