Metamath Proof Explorer


Theorem chjatom

Description: The join of a closed subspace and an atom equals their subspace sum. Special case of remark in Kalmbach p. 65, stating that if A or B is finite-dimensional, then this equality holds. (Contributed by NM, 4-Jun-2004) (New usage is discouraged.)

Ref Expression
Assertion chjatom ⊢ A ∈ C ℋ ∧ B ∈ HAtoms → A + ℋ B = A ∨ ℋ B

Proof

Step Hyp Ref Expression
1 atom1d ⊢ B ∈ HAtoms ↔ ∃ x ∈ ℋ x ≠ 0 ℎ ∧ B = span ⁡ x
2 spansnj ⊢ A ∈ C ℋ ∧ x ∈ ℋ → A + ℋ span ⁡ x = A ∨ ℋ span ⁡ x
3 oveq2 ⊢ B = span ⁡ x → A + ℋ B = A + ℋ span ⁡ x
4 oveq2 ⊢ B = span ⁡ x → A ∨ ℋ B = A ∨ ℋ span ⁡ x
5 3 4 eqeq12d ⊢ B = span ⁡ x → A + ℋ B = A ∨ ℋ B ↔ A + ℋ span ⁡ x = A ∨ ℋ span ⁡ x
6 2 5 imbitrrid ⊢ B = span ⁡ x → A ∈ C ℋ ∧ x ∈ ℋ → A + ℋ B = A ∨ ℋ B
7 6 expd ⊢ B = span ⁡ x → A ∈ C ℋ → x ∈ ℋ → A + ℋ B = A ∨ ℋ B
8 7 adantl ⊢ x ≠ 0 ℎ ∧ B = span ⁡ x → A ∈ C ℋ → x ∈ ℋ → A + ℋ B = A ∨ ℋ B
9 8 com3l ⊢ A ∈ C ℋ → x ∈ ℋ → x ≠ 0 ℎ ∧ B = span ⁡ x → A + ℋ B = A ∨ ℋ B
10 9 rexlimdv ⊢ A ∈ C ℋ → ∃ x ∈ ℋ x ≠ 0 ℎ ∧ B = span ⁡ x → A + ℋ B = A ∨ ℋ B
11 1 10 biimtrid ⊢ A ∈ C ℋ → B ∈ HAtoms → A + ℋ B = A ∨ ℋ B
12 11 imp ⊢ A ∈ C ℋ ∧ B ∈ HAtoms → A + ℋ B = A ∨ ℋ B