Metamath Proof Explorer


Theorem chpmatval2

Description: The characteristic polynomial of a (square) matrix (expressed with the Leibnitz formula for the determinant). (Contributed by AV, 2-Aug-2019)

Ref Expression
Hypotheses chpmatply1.c ⊢ C = N CharPlyMat R
chpmatply1.a ⊢ A = N Mat R
chpmatply1.b ⊢ B = Base A
chpmatply1.p ⊢ P = Poly 1 ⁡ R
chpmatval2.y ⊢ Y = N Mat P
chpmatval2.m1 ⊢ - ˙ = - Y
chpmatval2.x ⊢ X = var 1 ⁡ R
chpmatval2.t1 ⊢ · ˙ = ⋅ Y
chpmatval2.t ⊢ T = N matToPolyMat R
chpmatval2.i ⊢ 1 ˙ = 1 Y
chpmatval2.g ⊢ G = SymGrp ⁡ N
chpmatval2.h ⊢ H = Base G
chpmatval2.z ⊢ Z = ℤRHom ⁡ P
chpmatval2.s ⊢ S = pmSgn ⁡ N
chpmatval2.u ⊢ U = mulGrp P
chpmatval2.rm ⊢ × ˙ = ⋅ P
Assertion chpmatval2 ⊢ N ∈ Fin ∧ R ∈ Ring ∧ M ∈ B → C ⁡ M = ∑ P p ∈ H Z ∘ S ⁡ p × ˙ ∑ U x ∈ N p ⁡ x X · ˙ 1 ˙ - ˙ T ⁡ M x

Proof

Step Hyp Ref Expression
1 chpmatply1.c ⊢ C = N CharPlyMat R
2 chpmatply1.a ⊢ A = N Mat R
3 chpmatply1.b ⊢ B = Base A
4 chpmatply1.p ⊢ P = Poly 1 ⁡ R
5 chpmatval2.y ⊢ Y = N Mat P
6 chpmatval2.m1 ⊢ - ˙ = - Y
7 chpmatval2.x ⊢ X = var 1 ⁡ R
8 chpmatval2.t1 ⊢ · ˙ = ⋅ Y
9 chpmatval2.t ⊢ T = N matToPolyMat R
10 chpmatval2.i ⊢ 1 ˙ = 1 Y
11 chpmatval2.g ⊢ G = SymGrp ⁡ N
12 chpmatval2.h ⊢ H = Base G
13 chpmatval2.z ⊢ Z = ℤRHom ⁡ P
14 chpmatval2.s ⊢ S = pmSgn ⁡ N
15 chpmatval2.u ⊢ U = mulGrp P
16 chpmatval2.rm ⊢ × ˙ = ⋅ P
17 eqid ⊢ N maDet P = N maDet P
18 1 2 3 4 5 17 6 7 8 9 10 chpmatval ⊢ N ∈ Fin ∧ R ∈ Ring ∧ M ∈ B → C ⁡ M = N maDet P ⁡ X · ˙ 1 ˙ - ˙ T ⁡ M
19 eqid ⊢ N Mat P = N Mat P
20 5 fveq2i ⊢ - Y = - N Mat P
21 6 20 eqtri ⊢ - ˙ = - N Mat P
22 5 fveq2i ⊢ ⋅ Y = ⋅ N Mat P
23 8 22 eqtri ⊢ · ˙ = ⋅ N Mat P
24 5 fveq2i ⊢ 1 Y = 1 N Mat P
25 10 24 eqtri ⊢ 1 ˙ = 1 N Mat P
26 eqid ⊢ X · ˙ 1 ˙ - ˙ T ⁡ M = X · ˙ 1 ˙ - ˙ T ⁡ M
27 2 3 4 19 7 9 21 23 25 26 chmatcl ⊢ N ∈ Fin ∧ R ∈ Ring ∧ M ∈ B → X · ˙ 1 ˙ - ˙ T ⁡ M ∈ Base N Mat P
28 5 eqcomi ⊢ N Mat P = Y
29 28 fveq2i ⊢ Base N Mat P = Base Y
30 11 fveq2i ⊢ Base G = Base SymGrp ⁡ N
31 12 30 eqtri ⊢ H = Base SymGrp ⁡ N
32 17 5 29 31 13 14 16 15 mdetleib ⊢ X · ˙ 1 ˙ - ˙ T ⁡ M ∈ Base N Mat P → N maDet P ⁡ X · ˙ 1 ˙ - ˙ T ⁡ M = ∑ P p ∈ H Z ∘ S ⁡ p × ˙ ∑ U x ∈ N p ⁡ x X · ˙ 1 ˙ - ˙ T ⁡ M x
33 27 32 syl ⊢ N ∈ Fin ∧ R ∈ Ring ∧ M ∈ B → N maDet P ⁡ X · ˙ 1 ˙ - ˙ T ⁡ M = ∑ P p ∈ H Z ∘ S ⁡ p × ˙ ∑ U x ∈ N p ⁡ x X · ˙ 1 ˙ - ˙ T ⁡ M x
34 18 33 eqtrd ⊢ N ∈ Fin ∧ R ∈ Ring ∧ M ∈ B → C ⁡ M = ∑ P p ∈ H Z ∘ S ⁡ p × ˙ ∑ U x ∈ N p ⁡ x X · ˙ 1 ˙ - ˙ T ⁡ M x