Metamath Proof Explorer


Theorem chrdvds

Description: The ZZ ring homomorphism is zero only at multiples of the characteristic. (Contributed by Mario Carneiro, 23-Sep-2015)

Ref Expression
Hypotheses chrcl.c ⊢ C = chr ⁡ R
chrid.l ⊢ L = ℤRHom ⁡ R
chrid.z ⊢ 0 ˙ = 0 R
Assertion chrdvds ⊢ R ∈ Ring ∧ N ∈ ℤ → C ∥ N ↔ L ⁡ N = 0 ˙

Proof

Step Hyp Ref Expression
1 chrcl.c ⊢ C = chr ⁡ R
2 chrid.l ⊢ L = ℤRHom ⁡ R
3 chrid.z ⊢ 0 ˙ = 0 R
4 eqid ⊢ od ⁡ R = od ⁡ R
5 eqid ⊢ 1 R = 1 R
6 4 5 1 chrval ⊢ od ⁡ R ⁡ 1 R = C
7 6 breq1i ⊢ od ⁡ R ⁡ 1 R ∥ N ↔ C ∥ N
8 ringgrp ⊢ R ∈ Ring → R ∈ Grp
9 8 adantr ⊢ R ∈ Ring ∧ N ∈ ℤ → R ∈ Grp
10 eqid ⊢ Base R = Base R
11 10 5 ringidcl ⊢ R ∈ Ring → 1 R ∈ Base R
12 11 adantr ⊢ R ∈ Ring ∧ N ∈ ℤ → 1 R ∈ Base R
13 simpr ⊢ R ∈ Ring ∧ N ∈ ℤ → N ∈ ℤ
14 eqid ⊢ ⋅ R = ⋅ R
15 10 4 14 3 oddvds ⊢ R ∈ Grp ∧ 1 R ∈ Base R ∧ N ∈ ℤ → od ⁡ R ⁡ 1 R ∥ N ↔ N ⋅ R 1 R = 0 ˙
16 9 12 13 15 syl3anc ⊢ R ∈ Ring ∧ N ∈ ℤ → od ⁡ R ⁡ 1 R ∥ N ↔ N ⋅ R 1 R = 0 ˙
17 7 16 bitr3id ⊢ R ∈ Ring ∧ N ∈ ℤ → C ∥ N ↔ N ⋅ R 1 R = 0 ˙
18 2 14 5 zrhmulg ⊢ R ∈ Ring ∧ N ∈ ℤ → L ⁡ N = N ⋅ R 1 R
19 18 eqeq1d ⊢ R ∈ Ring ∧ N ∈ ℤ → L ⁡ N = 0 ˙ ↔ N ⋅ R 1 R = 0 ˙
20 17 19 bitr4d ⊢ R ∈ Ring ∧ N ∈ ℤ → C ∥ N ↔ L ⁡ N = 0 ˙