Metamath Proof Explorer


Theorem cjadd

Description: Complex conjugate distributes over addition. Proposition 10-3.4(a) of Gleason p. 133. (Contributed by NM, 31-Jul-1999) (Revised by Mario Carneiro, 14-Jul-2014)

Ref Expression
Assertion cjadd ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B ‾ = A ‾ + B ‾

Proof

Step Hyp Ref Expression
1 readd ⊢ A ∈ ℂ ∧ B ∈ ℂ → ℜ ⁡ A + B = ℜ ⁡ A + ℜ ⁡ B
2 imadd ⊢ A ∈ ℂ ∧ B ∈ ℂ → ℑ ⁡ A + B = ℑ ⁡ A + ℑ ⁡ B
3 2 oveq2d ⊢ A ∈ ℂ ∧ B ∈ ℂ → i ⁢ ℑ ⁡ A + B = i ⁢ ℑ ⁡ A + ℑ ⁡ B
4 ax-icn ⊢ i ∈ ℂ
5 4 a1i ⊢ A ∈ ℂ ∧ B ∈ ℂ → i ∈ ℂ
6 imcl ⊢ A ∈ ℂ → ℑ ⁡ A ∈ ℝ
7 6 adantr ⊢ A ∈ ℂ ∧ B ∈ ℂ → ℑ ⁡ A ∈ ℝ
8 7 recnd ⊢ A ∈ ℂ ∧ B ∈ ℂ → ℑ ⁡ A ∈ ℂ
9 imcl ⊢ B ∈ ℂ → ℑ ⁡ B ∈ ℝ
10 9 adantl ⊢ A ∈ ℂ ∧ B ∈ ℂ → ℑ ⁡ B ∈ ℝ
11 10 recnd ⊢ A ∈ ℂ ∧ B ∈ ℂ → ℑ ⁡ B ∈ ℂ
12 5 8 11 adddid ⊢ A ∈ ℂ ∧ B ∈ ℂ → i ⁢ ℑ ⁡ A + ℑ ⁡ B = i ⁢ ℑ ⁡ A + i ⁢ ℑ ⁡ B
13 3 12 eqtrd ⊢ A ∈ ℂ ∧ B ∈ ℂ → i ⁢ ℑ ⁡ A + B = i ⁢ ℑ ⁡ A + i ⁢ ℑ ⁡ B
14 1 13 oveq12d ⊢ A ∈ ℂ ∧ B ∈ ℂ → ℜ ⁡ A + B − i ⁢ ℑ ⁡ A + B = ℜ ⁡ A + ℜ ⁡ B - i ⁢ ℑ ⁡ A + i ⁢ ℑ ⁡ B
15 recl ⊢ A ∈ ℂ → ℜ ⁡ A ∈ ℝ
16 15 adantr ⊢ A ∈ ℂ ∧ B ∈ ℂ → ℜ ⁡ A ∈ ℝ
17 16 recnd ⊢ A ∈ ℂ ∧ B ∈ ℂ → ℜ ⁡ A ∈ ℂ
18 recl ⊢ B ∈ ℂ → ℜ ⁡ B ∈ ℝ
19 18 adantl ⊢ A ∈ ℂ ∧ B ∈ ℂ → ℜ ⁡ B ∈ ℝ
20 19 recnd ⊢ A ∈ ℂ ∧ B ∈ ℂ → ℜ ⁡ B ∈ ℂ
21 mulcl ⊢ i ∈ ℂ ∧ ℑ ⁡ A ∈ ℂ → i ⁢ ℑ ⁡ A ∈ ℂ
22 4 8 21 sylancr ⊢ A ∈ ℂ ∧ B ∈ ℂ → i ⁢ ℑ ⁡ A ∈ ℂ
23 mulcl ⊢ i ∈ ℂ ∧ ℑ ⁡ B ∈ ℂ → i ⁢ ℑ ⁡ B ∈ ℂ
24 4 11 23 sylancr ⊢ A ∈ ℂ ∧ B ∈ ℂ → i ⁢ ℑ ⁡ B ∈ ℂ
25 17 20 22 24 addsub4d ⊢ A ∈ ℂ ∧ B ∈ ℂ → ℜ ⁡ A + ℜ ⁡ B - i ⁢ ℑ ⁡ A + i ⁢ ℑ ⁡ B = ℜ ⁡ A − i ⁢ ℑ ⁡ A + ℜ ⁡ B - i ⁢ ℑ ⁡ B
26 14 25 eqtrd ⊢ A ∈ ℂ ∧ B ∈ ℂ → ℜ ⁡ A + B − i ⁢ ℑ ⁡ A + B = ℜ ⁡ A − i ⁢ ℑ ⁡ A + ℜ ⁡ B - i ⁢ ℑ ⁡ B
27 addcl ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B ∈ ℂ
28 remim ⊢ A + B ∈ ℂ → A + B ‾ = ℜ ⁡ A + B − i ⁢ ℑ ⁡ A + B
29 27 28 syl ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B ‾ = ℜ ⁡ A + B − i ⁢ ℑ ⁡ A + B
30 remim ⊢ A ∈ ℂ → A ‾ = ℜ ⁡ A − i ⁢ ℑ ⁡ A
31 remim ⊢ B ∈ ℂ → B ‾ = ℜ ⁡ B − i ⁢ ℑ ⁡ B
32 30 31 oveqan12d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A ‾ + B ‾ = ℜ ⁡ A − i ⁢ ℑ ⁡ A + ℜ ⁡ B - i ⁢ ℑ ⁡ B
33 26 29 32 3eqtr4d ⊢ A ∈ ℂ ∧ B ∈ ℂ → A + B ‾ = A ‾ + B ‾