Metamath Proof Explorer


Theorem cjdivd

Description: Complex conjugate distributes over division. (Contributed by Mario Carneiro, 29-May-2016)

Ref Expression
Hypotheses recld.1 ⊢ φ → A ∈ ℂ
readdd.2 ⊢ φ → B ∈ ℂ
cjdivd.2 ⊢ φ → B ≠ 0
Assertion cjdivd ⊢ φ → A B ‾ = A ‾ B ‾

Proof

Step Hyp Ref Expression
1 recld.1 ⊢ φ → A ∈ ℂ
2 readdd.2 ⊢ φ → B ∈ ℂ
3 cjdivd.2 ⊢ φ → B ≠ 0
4 cjdiv ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ B ≠ 0 → A B ‾ = A ‾ B ‾
5 1 2 3 4 syl3anc ⊢ φ → A B ‾ = A ‾ B ‾