Metamath Proof Explorer


Theorem cjexp

Description: Complex conjugate of positive integer exponentiation. (Contributed by NM, 7-Jun-2006)

Ref Expression
Assertion cjexp ⊢ A ∈ ℂ ∧ N ∈ ℕ 0 → A N ‾ = A ‾ N

Proof

Step Hyp Ref Expression
1 oveq2 ⊢ j = 0 → A j = A 0
2 1 fveq2d ⊢ j = 0 → A j ‾ = A 0 ‾
3 oveq2 ⊢ j = 0 → A ‾ j = A ‾ 0
4 2 3 eqeq12d ⊢ j = 0 → A j ‾ = A ‾ j ↔ A 0 ‾ = A ‾ 0
5 oveq2 ⊢ j = k → A j = A k
6 5 fveq2d ⊢ j = k → A j ‾ = A k ‾
7 oveq2 ⊢ j = k → A ‾ j = A ‾ k
8 6 7 eqeq12d ⊢ j = k → A j ‾ = A ‾ j ↔ A k ‾ = A ‾ k
9 oveq2 ⊢ j = k + 1 → A j = A k + 1
10 9 fveq2d ⊢ j = k + 1 → A j ‾ = A k + 1 ‾
11 oveq2 ⊢ j = k + 1 → A ‾ j = A ‾ k + 1
12 10 11 eqeq12d ⊢ j = k + 1 → A j ‾ = A ‾ j ↔ A k + 1 ‾ = A ‾ k + 1
13 oveq2 ⊢ j = N → A j = A N
14 13 fveq2d ⊢ j = N → A j ‾ = A N ‾
15 oveq2 ⊢ j = N → A ‾ j = A ‾ N
16 14 15 eqeq12d ⊢ j = N → A j ‾ = A ‾ j ↔ A N ‾ = A ‾ N
17 exp0 ⊢ A ∈ ℂ → A 0 = 1
18 17 fveq2d ⊢ A ∈ ℂ → A 0 ‾ = 1 ‾
19 cjcl ⊢ A ∈ ℂ → A ‾ ∈ ℂ
20 exp0 ⊢ A ‾ ∈ ℂ → A ‾ 0 = 1
21 1re ⊢ 1 ∈ ℝ
22 cjre ⊢ 1 ∈ ℝ → 1 ‾ = 1
23 21 22 ax-mp ⊢ 1 ‾ = 1
24 20 23 eqtr4di ⊢ A ‾ ∈ ℂ → A ‾ 0 = 1 ‾
25 19 24 syl ⊢ A ∈ ℂ → A ‾ 0 = 1 ‾
26 18 25 eqtr4d ⊢ A ∈ ℂ → A 0 ‾ = A ‾ 0
27 expp1 ⊢ A ∈ ℂ ∧ k ∈ ℕ 0 → A k + 1 = A k ⁢ A
28 27 fveq2d ⊢ A ∈ ℂ ∧ k ∈ ℕ 0 → A k + 1 ‾ = A k ⁢ A ‾
29 expcl ⊢ A ∈ ℂ ∧ k ∈ ℕ 0 → A k ∈ ℂ
30 simpl ⊢ A ∈ ℂ ∧ k ∈ ℕ 0 → A ∈ ℂ
31 cjmul ⊢ A k ∈ ℂ ∧ A ∈ ℂ → A k ⁢ A ‾ = A k ‾ ⁢ A ‾
32 29 30 31 syl2anc ⊢ A ∈ ℂ ∧ k ∈ ℕ 0 → A k ⁢ A ‾ = A k ‾ ⁢ A ‾
33 28 32 eqtrd ⊢ A ∈ ℂ ∧ k ∈ ℕ 0 → A k + 1 ‾ = A k ‾ ⁢ A ‾
34 33 adantr ⊢ A ∈ ℂ ∧ k ∈ ℕ 0 ∧ A k ‾ = A ‾ k → A k + 1 ‾ = A k ‾ ⁢ A ‾
35 oveq1 ⊢ A k ‾ = A ‾ k → A k ‾ ⁢ A ‾ = A ‾ k ⁢ A ‾
36 expp1 ⊢ A ‾ ∈ ℂ ∧ k ∈ ℕ 0 → A ‾ k + 1 = A ‾ k ⁢ A ‾
37 19 36 sylan ⊢ A ∈ ℂ ∧ k ∈ ℕ 0 → A ‾ k + 1 = A ‾ k ⁢ A ‾
38 37 eqcomd ⊢ A ∈ ℂ ∧ k ∈ ℕ 0 → A ‾ k ⁢ A ‾ = A ‾ k + 1
39 35 38 sylan9eqr ⊢ A ∈ ℂ ∧ k ∈ ℕ 0 ∧ A k ‾ = A ‾ k → A k ‾ ⁢ A ‾ = A ‾ k + 1
40 34 39 eqtrd ⊢ A ∈ ℂ ∧ k ∈ ℕ 0 ∧ A k ‾ = A ‾ k → A k + 1 ‾ = A ‾ k + 1
41 4 8 12 16 26 40 nn0indd ⊢ A ∈ ℂ ∧ N ∈ ℕ 0 → A N ‾ = A ‾ N