Metamath Proof Explorer


Theorem clatl

Description: A complete lattice is a lattice. (Contributed by NM, 18-Sep-2011) TODO: use eqrelrdv2 to shorten proof and eliminate joindmss and meetdmss ?

Ref Expression
Assertion clatl ⊢ K ∈ CLat → K ∈ Lat

Proof

Step Hyp Ref Expression
1 eqid ⊢ Base K = Base K
2 eqid ⊢ join ⁡ K = join ⁡ K
3 simpl ⊢ K ∈ Poset ∧ dom ⁡ lub ⁡ K = 𝒫 Base K → K ∈ Poset
4 1 2 3 joindmss ⊢ K ∈ Poset ∧ dom ⁡ lub ⁡ K = 𝒫 Base K → dom ⁡ join ⁡ K ⊆ Base K × Base K
5 relxp ⊢ Rel ⁡ Base K × Base K
6 5 a1i ⊢ K ∈ Poset ∧ dom ⁡ lub ⁡ K = 𝒫 Base K → Rel ⁡ Base K × Base K
7 opelxp ⊢ x y ∈ Base K × Base K ↔ x ∈ Base K ∧ y ∈ Base K
8 vex ⊢ x ∈ V
9 vex ⊢ y ∈ V
10 8 9 prss ⊢ x ∈ Base K ∧ y ∈ Base K ↔ x y ⊆ Base K
11 7 10 sylbb ⊢ x y ∈ Base K × Base K → x y ⊆ Base K
12 prex ⊢ x y ∈ V
13 12 elpw ⊢ x y ∈ 𝒫 Base K ↔ x y ⊆ Base K
14 11 13 sylibr ⊢ x y ∈ Base K × Base K → x y ∈ 𝒫 Base K
15 eleq2 ⊢ dom ⁡ lub ⁡ K = 𝒫 Base K → x y ∈ dom ⁡ lub ⁡ K ↔ x y ∈ 𝒫 Base K
16 14 15 imbitrrid ⊢ dom ⁡ lub ⁡ K = 𝒫 Base K → x y ∈ Base K × Base K → x y ∈ dom ⁡ lub ⁡ K
17 16 adantl ⊢ K ∈ Poset ∧ dom ⁡ lub ⁡ K = 𝒫 Base K → x y ∈ Base K × Base K → x y ∈ dom ⁡ lub ⁡ K
18 eqid ⊢ lub ⁡ K = lub ⁡ K
19 8 a1i ⊢ K ∈ Poset ∧ dom ⁡ lub ⁡ K = 𝒫 Base K → x ∈ V
20 9 a1i ⊢ K ∈ Poset ∧ dom ⁡ lub ⁡ K = 𝒫 Base K → y ∈ V
21 18 2 3 19 20 joindef ⊢ K ∈ Poset ∧ dom ⁡ lub ⁡ K = 𝒫 Base K → x y ∈ dom ⁡ join ⁡ K ↔ x y ∈ dom ⁡ lub ⁡ K
22 17 21 sylibrd ⊢ K ∈ Poset ∧ dom ⁡ lub ⁡ K = 𝒫 Base K → x y ∈ Base K × Base K → x y ∈ dom ⁡ join ⁡ K
23 6 22 relssdv ⊢ K ∈ Poset ∧ dom ⁡ lub ⁡ K = 𝒫 Base K → Base K × Base K ⊆ dom ⁡ join ⁡ K
24 4 23 eqssd ⊢ K ∈ Poset ∧ dom ⁡ lub ⁡ K = 𝒫 Base K → dom ⁡ join ⁡ K = Base K × Base K
25 24 ex ⊢ K ∈ Poset → dom ⁡ lub ⁡ K = 𝒫 Base K → dom ⁡ join ⁡ K = Base K × Base K
26 eqid ⊢ meet ⁡ K = meet ⁡ K
27 simpl ⊢ K ∈ Poset ∧ dom ⁡ glb ⁡ K = 𝒫 Base K → K ∈ Poset
28 1 26 27 meetdmss ⊢ K ∈ Poset ∧ dom ⁡ glb ⁡ K = 𝒫 Base K → dom ⁡ meet ⁡ K ⊆ Base K × Base K
29 5 a1i ⊢ K ∈ Poset ∧ dom ⁡ glb ⁡ K = 𝒫 Base K → Rel ⁡ Base K × Base K
30 eleq2 ⊢ dom ⁡ glb ⁡ K = 𝒫 Base K → x y ∈ dom ⁡ glb ⁡ K ↔ x y ∈ 𝒫 Base K
31 14 30 imbitrrid ⊢ dom ⁡ glb ⁡ K = 𝒫 Base K → x y ∈ Base K × Base K → x y ∈ dom ⁡ glb ⁡ K
32 31 adantl ⊢ K ∈ Poset ∧ dom ⁡ glb ⁡ K = 𝒫 Base K → x y ∈ Base K × Base K → x y ∈ dom ⁡ glb ⁡ K
33 eqid ⊢ glb ⁡ K = glb ⁡ K
34 8 a1i ⊢ K ∈ Poset ∧ dom ⁡ glb ⁡ K = 𝒫 Base K → x ∈ V
35 9 a1i ⊢ K ∈ Poset ∧ dom ⁡ glb ⁡ K = 𝒫 Base K → y ∈ V
36 33 26 27 34 35 meetdef ⊢ K ∈ Poset ∧ dom ⁡ glb ⁡ K = 𝒫 Base K → x y ∈ dom ⁡ meet ⁡ K ↔ x y ∈ dom ⁡ glb ⁡ K
37 32 36 sylibrd ⊢ K ∈ Poset ∧ dom ⁡ glb ⁡ K = 𝒫 Base K → x y ∈ Base K × Base K → x y ∈ dom ⁡ meet ⁡ K
38 29 37 relssdv ⊢ K ∈ Poset ∧ dom ⁡ glb ⁡ K = 𝒫 Base K → Base K × Base K ⊆ dom ⁡ meet ⁡ K
39 28 38 eqssd ⊢ K ∈ Poset ∧ dom ⁡ glb ⁡ K = 𝒫 Base K → dom ⁡ meet ⁡ K = Base K × Base K
40 39 ex ⊢ K ∈ Poset → dom ⁡ glb ⁡ K = 𝒫 Base K → dom ⁡ meet ⁡ K = Base K × Base K
41 25 40 anim12d ⊢ K ∈ Poset → dom ⁡ lub ⁡ K = 𝒫 Base K ∧ dom ⁡ glb ⁡ K = 𝒫 Base K → dom ⁡ join ⁡ K = Base K × Base K ∧ dom ⁡ meet ⁡ K = Base K × Base K
42 41 imdistani ⊢ K ∈ Poset ∧ dom ⁡ lub ⁡ K = 𝒫 Base K ∧ dom ⁡ glb ⁡ K = 𝒫 Base K → K ∈ Poset ∧ dom ⁡ join ⁡ K = Base K × Base K ∧ dom ⁡ meet ⁡ K = Base K × Base K
43 1 18 33 isclat ⊢ K ∈ CLat ↔ K ∈ Poset ∧ dom ⁡ lub ⁡ K = 𝒫 Base K ∧ dom ⁡ glb ⁡ K = 𝒫 Base K
44 1 2 26 islat ⊢ K ∈ Lat ↔ K ∈ Poset ∧ dom ⁡ join ⁡ K = Base K × Base K ∧ dom ⁡ meet ⁡ K = Base K × Base K
45 42 43 44 3imtr4i ⊢ K ∈ CLat → K ∈ Lat