Metamath Proof Explorer


Theorem clim2cf

Description: Express the predicate F converges to A . Similar to clim2 , but without the disjoint var constraint F k . (Contributed by Glauco Siliprandi, 11-Dec-2019)

Ref Expression
Hypotheses clim2cf.nf ⊢ Ⅎ _ k F
clim2cf.z ⊢ Z = ℤ ≥ M
clim2cf.m ⊢ φ → M ∈ ℤ
clim2cf.f ⊢ φ → F ∈ V
clim2cf.fv ⊢ φ ∧ k ∈ Z → F ⁡ k = B
clim2cf.a ⊢ φ → A ∈ ℂ
clim2cf.b ⊢ φ ∧ k ∈ Z → B ∈ ℂ
Assertion clim2cf ⊢ φ → F ⇝ A ↔ ∀ x ∈ ℝ + ∃ j ∈ Z ∀ k ∈ ℤ ≥ j B − A < x

Proof

Step Hyp Ref Expression
1 clim2cf.nf ⊢ Ⅎ _ k F
2 clim2cf.z ⊢ Z = ℤ ≥ M
3 clim2cf.m ⊢ φ → M ∈ ℤ
4 clim2cf.f ⊢ φ → F ∈ V
5 clim2cf.fv ⊢ φ ∧ k ∈ Z → F ⁡ k = B
6 clim2cf.a ⊢ φ → A ∈ ℂ
7 clim2cf.b ⊢ φ ∧ k ∈ Z → B ∈ ℂ
8 6 biantrurd ⊢ φ → ∀ x ∈ ℝ + ∃ j ∈ Z ∀ k ∈ ℤ ≥ j B ∈ ℂ ∧ B − A < x ↔ A ∈ ℂ ∧ ∀ x ∈ ℝ + ∃ j ∈ Z ∀ k ∈ ℤ ≥ j B ∈ ℂ ∧ B − A < x
9 2 uztrn2 ⊢ j ∈ Z ∧ k ∈ ℤ ≥ j → k ∈ Z
10 7 biantrurd ⊢ φ ∧ k ∈ Z → B − A < x ↔ B ∈ ℂ ∧ B − A < x
11 9 10 sylan2 ⊢ φ ∧ j ∈ Z ∧ k ∈ ℤ ≥ j → B − A < x ↔ B ∈ ℂ ∧ B − A < x
12 11 anassrs ⊢ φ ∧ j ∈ Z ∧ k ∈ ℤ ≥ j → B − A < x ↔ B ∈ ℂ ∧ B − A < x
13 12 ralbidva ⊢ φ ∧ j ∈ Z → ∀ k ∈ ℤ ≥ j B − A < x ↔ ∀ k ∈ ℤ ≥ j B ∈ ℂ ∧ B − A < x
14 13 rexbidva ⊢ φ → ∃ j ∈ Z ∀ k ∈ ℤ ≥ j B − A < x ↔ ∃ j ∈ Z ∀ k ∈ ℤ ≥ j B ∈ ℂ ∧ B − A < x
15 14 ralbidv ⊢ φ → ∀ x ∈ ℝ + ∃ j ∈ Z ∀ k ∈ ℤ ≥ j B − A < x ↔ ∀ x ∈ ℝ + ∃ j ∈ Z ∀ k ∈ ℤ ≥ j B ∈ ℂ ∧ B − A < x
16 1 2 3 4 5 clim2f ⊢ φ → F ⇝ A ↔ A ∈ ℂ ∧ ∀ x ∈ ℝ + ∃ j ∈ Z ∀ k ∈ ℤ ≥ j B ∈ ℂ ∧ B − A < x
17 8 15 16 3bitr4rd ⊢ φ → F ⇝ A ↔ ∀ x ∈ ℝ + ∃ j ∈ Z ∀ k ∈ ℤ ≥ j B − A < x