Metamath Proof Explorer


Theorem climdivf

Description: Limit of the ratio of two converging sequences. (Contributed by Glauco Siliprandi, 29-Jun-2017)

Ref Expression
Hypotheses climdivf.1 ⊢ Ⅎ k φ
climdivf.2 ⊢ Ⅎ _ k F
climdivf.3 ⊢ Ⅎ _ k G
climdivf.4 ⊢ Ⅎ _ k H
climdivf.5 ⊢ Z = ℤ ≥ M
climdivf.6 ⊢ φ → M ∈ ℤ
climdivf.7 ⊢ φ → F ⇝ A
climdivf.8 ⊢ φ → H ∈ X
climdivf.9 ⊢ φ → G ⇝ B
climdivf.10 ⊢ φ → B ≠ 0
climdivf.11 ⊢ φ ∧ k ∈ Z → F ⁡ k ∈ ℂ
climdivf.12 ⊢ φ ∧ k ∈ Z → G ⁡ k ∈ ℂ ∖ 0
climdivf.13 ⊢ φ ∧ k ∈ Z → H ⁡ k = F ⁡ k G ⁡ k
Assertion climdivf ⊢ φ → H ⇝ A B

Proof

Step Hyp Ref Expression
1 climdivf.1 ⊢ Ⅎ k φ
2 climdivf.2 ⊢ Ⅎ _ k F
3 climdivf.3 ⊢ Ⅎ _ k G
4 climdivf.4 ⊢ Ⅎ _ k H
5 climdivf.5 ⊢ Z = ℤ ≥ M
6 climdivf.6 ⊢ φ → M ∈ ℤ
7 climdivf.7 ⊢ φ → F ⇝ A
8 climdivf.8 ⊢ φ → H ∈ X
9 climdivf.9 ⊢ φ → G ⇝ B
10 climdivf.10 ⊢ φ → B ≠ 0
11 climdivf.11 ⊢ φ ∧ k ∈ Z → F ⁡ k ∈ ℂ
12 climdivf.12 ⊢ φ ∧ k ∈ Z → G ⁡ k ∈ ℂ ∖ 0
13 climdivf.13 ⊢ φ ∧ k ∈ Z → H ⁡ k = F ⁡ k G ⁡ k
14 nfmpt1 ⊢ Ⅎ _ k k ∈ Z ⟼ 1 G ⁡ k
15 simpr ⊢ φ ∧ k ∈ Z → k ∈ Z
16 12 eldifad ⊢ φ ∧ k ∈ Z → G ⁡ k ∈ ℂ
17 eldifsni ⊢ G ⁡ k ∈ ℂ ∖ 0 → G ⁡ k ≠ 0
18 12 17 syl ⊢ φ ∧ k ∈ Z → G ⁡ k ≠ 0
19 16 18 reccld ⊢ φ ∧ k ∈ Z → 1 G ⁡ k ∈ ℂ
20 eqid ⊢ k ∈ Z ⟼ 1 G ⁡ k = k ∈ Z ⟼ 1 G ⁡ k
21 20 fvmpt2 ⊢ k ∈ Z ∧ 1 G ⁡ k ∈ ℂ → k ∈ Z ⟼ 1 G ⁡ k ⁡ k = 1 G ⁡ k
22 15 19 21 syl2anc ⊢ φ ∧ k ∈ Z → k ∈ Z ⟼ 1 G ⁡ k ⁡ k = 1 G ⁡ k
23 5 fvexi ⊢ Z ∈ V
24 23 mptex ⊢ k ∈ Z ⟼ 1 G ⁡ k ∈ V
25 24 a1i ⊢ φ → k ∈ Z ⟼ 1 G ⁡ k ∈ V
26 1 3 14 5 6 9 10 12 22 25 climrecf ⊢ φ → k ∈ Z ⟼ 1 G ⁡ k ⇝ 1 B
27 22 19 eqeltrd ⊢ φ ∧ k ∈ Z → k ∈ Z ⟼ 1 G ⁡ k ⁡ k ∈ ℂ
28 11 16 18 divrecd ⊢ φ ∧ k ∈ Z → F ⁡ k G ⁡ k = F ⁡ k ⁢ 1 G ⁡ k
29 22 eqcomd ⊢ φ ∧ k ∈ Z → 1 G ⁡ k = k ∈ Z ⟼ 1 G ⁡ k ⁡ k
30 29 oveq2d ⊢ φ ∧ k ∈ Z → F ⁡ k ⁢ 1 G ⁡ k = F ⁡ k ⁢ k ∈ Z ⟼ 1 G ⁡ k ⁡ k
31 13 28 30 3eqtrd ⊢ φ ∧ k ∈ Z → H ⁡ k = F ⁡ k ⁢ k ∈ Z ⟼ 1 G ⁡ k ⁡ k
32 1 2 14 4 5 6 7 8 26 11 27 31 climmulf ⊢ φ → H ⇝ A ⁢ 1 B
33 climcl ⊢ F ⇝ A → A ∈ ℂ
34 7 33 syl ⊢ φ → A ∈ ℂ
35 climcl ⊢ G ⇝ B → B ∈ ℂ
36 9 35 syl ⊢ φ → B ∈ ℂ
37 34 36 10 divrecd ⊢ φ → A B = A ⁢ 1 B
38 32 37 breqtrrd ⊢ φ → H ⇝ A B