Metamath Proof Explorer


Theorem climmulf

Description: A version of climmul using bound-variable hypotheses instead of distinct variable conditions. (Contributed by Glauco Siliprandi, 29-Jun-2017)

Ref Expression
Hypotheses climmulf.1 ⊢ Ⅎ k φ
climmulf.2 ⊢ Ⅎ _ k F
climmulf.3 ⊢ Ⅎ _ k G
climmulf.4 ⊢ Ⅎ _ k H
climmulf.5 ⊢ Z = ℤ ≥ M
climmulf.6 ⊢ φ → M ∈ ℤ
climmulf.7 ⊢ φ → F ⇝ A
climmulf.8 ⊢ φ → H ∈ X
climmulf.9 ⊢ φ → G ⇝ B
climmulf.10 ⊢ φ ∧ k ∈ Z → F ⁡ k ∈ ℂ
climmulf.11 ⊢ φ ∧ k ∈ Z → G ⁡ k ∈ ℂ
climmulf.12 ⊢ φ ∧ k ∈ Z → H ⁡ k = F ⁡ k ⁢ G ⁡ k
Assertion climmulf ⊢ φ → H ⇝ A ⁢ B

Proof

Step Hyp Ref Expression
1 climmulf.1 ⊢ Ⅎ k φ
2 climmulf.2 ⊢ Ⅎ _ k F
3 climmulf.3 ⊢ Ⅎ _ k G
4 climmulf.4 ⊢ Ⅎ _ k H
5 climmulf.5 ⊢ Z = ℤ ≥ M
6 climmulf.6 ⊢ φ → M ∈ ℤ
7 climmulf.7 ⊢ φ → F ⇝ A
8 climmulf.8 ⊢ φ → H ∈ X
9 climmulf.9 ⊢ φ → G ⇝ B
10 climmulf.10 ⊢ φ ∧ k ∈ Z → F ⁡ k ∈ ℂ
11 climmulf.11 ⊢ φ ∧ k ∈ Z → G ⁡ k ∈ ℂ
12 climmulf.12 ⊢ φ ∧ k ∈ Z → H ⁡ k = F ⁡ k ⁢ G ⁡ k
13 nfcv ⊢ Ⅎ _ k j
14 13 nfel1 ⊢ Ⅎ k j ∈ Z
15 1 14 nfan ⊢ Ⅎ k φ ∧ j ∈ Z
16 2 13 nffv ⊢ Ⅎ _ k F ⁡ j
17 16 nfel1 ⊢ Ⅎ k F ⁡ j ∈ ℂ
18 15 17 nfim ⊢ Ⅎ k φ ∧ j ∈ Z → F ⁡ j ∈ ℂ
19 eleq1w ⊢ k = j → k ∈ Z ↔ j ∈ Z
20 19 anbi2d ⊢ k = j → φ ∧ k ∈ Z ↔ φ ∧ j ∈ Z
21 fveq2 ⊢ k = j → F ⁡ k = F ⁡ j
22 21 eleq1d ⊢ k = j → F ⁡ k ∈ ℂ ↔ F ⁡ j ∈ ℂ
23 20 22 imbi12d ⊢ k = j → φ ∧ k ∈ Z → F ⁡ k ∈ ℂ ↔ φ ∧ j ∈ Z → F ⁡ j ∈ ℂ
24 18 23 10 chvarfv ⊢ φ ∧ j ∈ Z → F ⁡ j ∈ ℂ
25 3 13 nffv ⊢ Ⅎ _ k G ⁡ j
26 25 nfel1 ⊢ Ⅎ k G ⁡ j ∈ ℂ
27 15 26 nfim ⊢ Ⅎ k φ ∧ j ∈ Z → G ⁡ j ∈ ℂ
28 fveq2 ⊢ k = j → G ⁡ k = G ⁡ j
29 28 eleq1d ⊢ k = j → G ⁡ k ∈ ℂ ↔ G ⁡ j ∈ ℂ
30 20 29 imbi12d ⊢ k = j → φ ∧ k ∈ Z → G ⁡ k ∈ ℂ ↔ φ ∧ j ∈ Z → G ⁡ j ∈ ℂ
31 27 30 11 chvarfv ⊢ φ ∧ j ∈ Z → G ⁡ j ∈ ℂ
32 4 13 nffv ⊢ Ⅎ _ k H ⁡ j
33 nfcv ⊢ Ⅎ _ k ×
34 16 33 25 nfov ⊢ Ⅎ _ k F ⁡ j ⁢ G ⁡ j
35 32 34 nfeq ⊢ Ⅎ k H ⁡ j = F ⁡ j ⁢ G ⁡ j
36 15 35 nfim ⊢ Ⅎ k φ ∧ j ∈ Z → H ⁡ j = F ⁡ j ⁢ G ⁡ j
37 fveq2 ⊢ k = j → H ⁡ k = H ⁡ j
38 21 28 oveq12d ⊢ k = j → F ⁡ k ⁢ G ⁡ k = F ⁡ j ⁢ G ⁡ j
39 37 38 eqeq12d ⊢ k = j → H ⁡ k = F ⁡ k ⁢ G ⁡ k ↔ H ⁡ j = F ⁡ j ⁢ G ⁡ j
40 20 39 imbi12d ⊢ k = j → φ ∧ k ∈ Z → H ⁡ k = F ⁡ k ⁢ G ⁡ k ↔ φ ∧ j ∈ Z → H ⁡ j = F ⁡ j ⁢ G ⁡ j
41 36 40 12 chvarfv ⊢ φ ∧ j ∈ Z → H ⁡ j = F ⁡ j ⁢ G ⁡ j
42 5 6 7 8 9 24 31 41 climmul ⊢ φ → H ⇝ A ⁢ B