Metamath Proof Explorer


Theorem cnfldnm

Description: The norm of the field of complex numbers. (Contributed by Mario Carneiro, 4-Oct-2015)

Ref Expression
Assertion cnfldnm abs = norm fld

Proof

Step Hyp Ref Expression
1 0cn 0
2 eqid abs = abs
3 2 cnmetdval x 0 x abs 0 = x 0
4 1 3 mpan2 x x abs 0 = x 0
5 subid1 x x 0 = x
6 5 fveq2d x x 0 = x
7 4 6 eqtrd x x abs 0 = x
8 7 mpteq2ia x x abs 0 = x x
9 eqid norm fld = norm fld
10 cnfldbas = Base fld
11 cnfld0 0 = 0 fld
12 cnfldds abs = dist fld
13 9 10 11 12 nmfval norm fld = x x abs 0
14 absf abs :
15 14 a1i abs :
16 15 feqmptd abs = x x
17 16 mptru abs = x x
18 8 13 17 3eqtr4ri abs = norm fld