Metamath Proof Explorer


Theorem cntzidss

Description: If the elements of S commute, the elements of a subset T also commute. (Contributed by Mario Carneiro, 25-Apr-2016)

Ref Expression
Hypothesis cntzmhm.z ⊢ Z = Cntz ⁡ G
Assertion cntzidss ⊢ S ⊆ Z ⁡ S ∧ T ⊆ S → T ⊆ Z ⁡ T

Proof

Step Hyp Ref Expression
1 cntzmhm.z ⊢ Z = Cntz ⁡ G
2 simpr ⊢ S ⊆ Z ⁡ S ∧ T ⊆ S → T ⊆ S
3 simpl ⊢ S ⊆ Z ⁡ S ∧ T ⊆ S → S ⊆ Z ⁡ S
4 eqid ⊢ Base G = Base G
5 4 1 cntzssv ⊢ Z ⁡ S ⊆ Base G
6 3 5 sstrdi ⊢ S ⊆ Z ⁡ S ∧ T ⊆ S → S ⊆ Base G
7 4 1 cntz2ss ⊢ S ⊆ Base G ∧ T ⊆ S → Z ⁡ S ⊆ Z ⁡ T
8 6 7 sylancom ⊢ S ⊆ Z ⁡ S ∧ T ⊆ S → Z ⁡ S ⊆ Z ⁡ T
9 3 8 sstrd ⊢ S ⊆ Z ⁡ S ∧ T ⊆ S → S ⊆ Z ⁡ T
10 2 9 sstrd ⊢ S ⊆ Z ⁡ S ∧ T ⊆ S → T ⊆ Z ⁡ T