Metamath Proof Explorer


Theorem cnvco1

Description: Another distributive law of converse over class composition. (Contributed by Scott Fenton, 3-May-2014)

Ref Expression
Assertion cnvco1 ⊢ A -1 ∘ B -1 = B -1 ∘ A

Proof

Step Hyp Ref Expression
1 relcnv ⊢ Rel ⁡ A -1 ∘ B -1
2 relco ⊢ Rel ⁡ B -1 ∘ A
3 vex ⊢ z ∈ V
4 vex ⊢ y ∈ V
5 3 4 brcnv ⊢ z B -1 y ↔ y B z
6 5 bicomi ⊢ y B z ↔ z B -1 y
7 vex ⊢ x ∈ V
8 3 7 brcnv ⊢ z A -1 x ↔ x A z
9 6 8 anbi12ci ⊢ y B z ∧ z A -1 x ↔ x A z ∧ z B -1 y
10 9 exbii ⊢ ∃ z y B z ∧ z A -1 x ↔ ∃ z x A z ∧ z B -1 y
11 7 4 opelcnv ⊢ x y ∈ A -1 ∘ B -1 ↔ y x ∈ A -1 ∘ B
12 4 7 opelco ⊢ y x ∈ A -1 ∘ B ↔ ∃ z y B z ∧ z A -1 x
13 11 12 bitri ⊢ x y ∈ A -1 ∘ B -1 ↔ ∃ z y B z ∧ z A -1 x
14 7 4 opelco ⊢ x y ∈ B -1 ∘ A ↔ ∃ z x A z ∧ z B -1 y
15 10 13 14 3bitr4i ⊢ x y ∈ A -1 ∘ B -1 ↔ x y ∈ B -1 ∘ A
16 1 2 15 eqrelriiv ⊢ A -1 ∘ B -1 = B -1 ∘ A