Metamath Proof Explorer


Theorem cnvco2

Description: Another distributive law of converse over class composition. (Contributed by Scott Fenton, 3-May-2014)

Ref Expression
Assertion cnvco2 ⊢ A ∘ B -1 -1 = B ∘ A -1

Proof

Step Hyp Ref Expression
1 relcnv ⊢ Rel ⁡ A ∘ B -1 -1
2 relco ⊢ Rel ⁡ B ∘ A -1
3 vex ⊢ y ∈ V
4 vex ⊢ z ∈ V
5 3 4 brcnv ⊢ y B -1 z ↔ z B y
6 vex ⊢ x ∈ V
7 6 4 brcnv ⊢ x A -1 z ↔ z A x
8 7 bicomi ⊢ z A x ↔ x A -1 z
9 5 8 anbi12ci ⊢ y B -1 z ∧ z A x ↔ x A -1 z ∧ z B y
10 9 exbii ⊢ ∃ z y B -1 z ∧ z A x ↔ ∃ z x A -1 z ∧ z B y
11 6 3 opelcnv ⊢ x y ∈ A ∘ B -1 -1 ↔ y x ∈ A ∘ B -1
12 3 6 opelco ⊢ y x ∈ A ∘ B -1 ↔ ∃ z y B -1 z ∧ z A x
13 11 12 bitri ⊢ x y ∈ A ∘ B -1 -1 ↔ ∃ z y B -1 z ∧ z A x
14 6 3 opelco ⊢ x y ∈ B ∘ A -1 ↔ ∃ z x A -1 z ∧ z B y
15 10 13 14 3bitr4i ⊢ x y ∈ A ∘ B -1 -1 ↔ x y ∈ B ∘ A -1
16 1 2 15 eqrelriiv ⊢ A ∘ B -1 -1 = B ∘ A -1