Metamath Proof Explorer


Theorem coeq2d

Description: Equality deduction for composition of two classes. (Contributed by NM, 16-Nov-2000)

Ref Expression
Hypothesis coeq1d.1 φ A = B
Assertion coeq2d φ C A = C B

Proof

Step Hyp Ref Expression
1 coeq1d.1 φ A = B
2 coeq2 A = B C A = C B
3 1 2 syl φ C A = C B