Metamath Proof Explorer


Theorem coeval

Description: Value of the coefficient function. (Contributed by Mario Carneiro, 22-Jul-2014)

Ref Expression
Assertion coeval ⊢ F ∈ Poly ⁡ S → coeff ⁡ F = ι a ∈ ℂ ℕ 0 | ∃ n ∈ ℕ 0 a ℤ ≥ n + 1 = 0 ∧ F = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k

Proof

Step Hyp Ref Expression
1 plyssc ⊢ Poly ⁡ S ⊆ Poly ⁡ ℂ
2 1 sseli ⊢ F ∈ Poly ⁡ S → F ∈ Poly ⁡ ℂ
3 eqeq1 ⊢ f = F → f = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k ↔ F = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k
4 3 anbi2d ⊢ f = F → a ℤ ≥ n + 1 = 0 ∧ f = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k ↔ a ℤ ≥ n + 1 = 0 ∧ F = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k
5 4 rexbidv ⊢ f = F → ∃ n ∈ ℕ 0 a ℤ ≥ n + 1 = 0 ∧ f = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k ↔ ∃ n ∈ ℕ 0 a ℤ ≥ n + 1 = 0 ∧ F = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k
6 5 riotabidv ⊢ f = F → ι a ∈ ℂ ℕ 0 | ∃ n ∈ ℕ 0 a ℤ ≥ n + 1 = 0 ∧ f = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k = ι a ∈ ℂ ℕ 0 | ∃ n ∈ ℕ 0 a ℤ ≥ n + 1 = 0 ∧ F = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k
7 df-coe ⊢ coeff = f ∈ Poly ⁡ ℂ ⟼ ι a ∈ ℂ ℕ 0 | ∃ n ∈ ℕ 0 a ℤ ≥ n + 1 = 0 ∧ f = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k
8 riotaex ⊢ ι a ∈ ℂ ℕ 0 | ∃ n ∈ ℕ 0 a ℤ ≥ n + 1 = 0 ∧ F = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k ∈ V
9 6 7 8 fvmpt ⊢ F ∈ Poly ⁡ ℂ → coeff ⁡ F = ι a ∈ ℂ ℕ 0 | ∃ n ∈ ℕ 0 a ℤ ≥ n + 1 = 0 ∧ F = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k
10 2 9 syl ⊢ F ∈ Poly ⁡ S → coeff ⁡ F = ι a ∈ ℂ ℕ 0 | ∃ n ∈ ℕ 0 a ℤ ≥ n + 1 = 0 ∧ F = z ∈ ℂ ⟼ ∑ k = 0 n a ⁡ k ⁢ z k