Metamath Proof Explorer


Theorem cofcutrtime1d

Description: If X is a timely cut of A and B , then ( _LeftX ) is cofinal with A . (Contributed by Scott Fenton, 23-Jan-2025)

Ref Expression
Hypotheses cofcutrtimed.1 ⊢ φ → A ∪ B ⊆ Old ⁡ bday ⁡ X
cofcutrtimed.2 ⊢ φ → A ≪ s B
cofcutrtimed.3 ⊢ φ → X = A | s B
Assertion cofcutrtime1d ⊢ φ → ∀ x ∈ A ∃ y ∈ L ⁡ X x ≤ s y

Proof

Step Hyp Ref Expression
1 cofcutrtimed.1 ⊢ φ → A ∪ B ⊆ Old ⁡ bday ⁡ X
2 cofcutrtimed.2 ⊢ φ → A ≪ s B
3 cofcutrtimed.3 ⊢ φ → X = A | s B
4 cofcutrtime ⊢ A ∪ B ⊆ Old ⁡ bday ⁡ X ∧ A ≪ s B ∧ X = A | s B → ∀ x ∈ A ∃ y ∈ L ⁡ X x ≤ s y ∧ ∀ z ∈ B ∃ w ∈ R ⁡ X w ≤ s z
5 1 2 3 4 syl3anc ⊢ φ → ∀ x ∈ A ∃ y ∈ L ⁡ X x ≤ s y ∧ ∀ z ∈ B ∃ w ∈ R ⁡ X w ≤ s z
6 5 simpld ⊢ φ → ∀ x ∈ A ∃ y ∈ L ⁡ X x ≤ s y