Metamath Proof Explorer


Theorem cofidf2

Description: If " F is a section of G " in a category of small categories (in a universe), then the morphism part of F is injective, and the morphism part of G is surjective in the image of F . (Contributed by Zhi Wang, 15-Nov-2025)

Ref Expression
Hypotheses cofidval.i ⊢ I = id func ⁡ D
cofidval.b ⊢ B = Base D
cofidval.f ⊢ φ → F D Func E G
cofidval.k ⊢ φ → K E Func D L
cofidval.o ⊢ φ → K L ∘ func F G = I
cofidval.h ⊢ H = Hom ⁡ D
cofidf2.j ⊢ J = Hom ⁡ E
cofidf2.x ⊢ φ → X ∈ B
cofidf2.y ⊢ φ → Y ∈ B
Assertion cofidf2 ⊢ φ → X G Y : X H Y ⟶ 1-1 F ⁡ X J F ⁡ Y ∧ F ⁡ X L F ⁡ Y : F ⁡ X J F ⁡ Y ⟶ onto X H Y

Proof

Step Hyp Ref Expression
1 cofidval.i ⊢ I = id func ⁡ D
2 cofidval.b ⊢ B = Base D
3 cofidval.f ⊢ φ → F D Func E G
4 cofidval.k ⊢ φ → K E Func D L
5 cofidval.o ⊢ φ → K L ∘ func F G = I
6 cofidval.h ⊢ H = Hom ⁡ D
7 cofidf2.j ⊢ J = Hom ⁡ E
8 cofidf2.x ⊢ φ → X ∈ B
9 cofidf2.y ⊢ φ → Y ∈ B
10 df-br ⊢ F D Func E G ↔ F G ∈ D Func E
11 3 10 sylib ⊢ φ → F G ∈ D Func E
12 df-br ⊢ K E Func D L ↔ K L ∈ E Func D
13 4 12 sylib ⊢ φ → K L ∈ E Func D
14 1 2 11 13 5 6 7 8 9 cofidf2a ⊢ φ → X 2 nd ⁡ F G Y : X H Y ⟶ 1-1 1 st ⁡ F G ⁡ X J 1 st ⁡ F G ⁡ Y ∧ 1 st ⁡ F G ⁡ X 2 nd ⁡ K L 1 st ⁡ F G ⁡ Y : 1 st ⁡ F G ⁡ X J 1 st ⁡ F G ⁡ Y ⟶ onto X H Y
15 3 func2nd ⊢ φ → 2 nd ⁡ F G = G
16 15 oveqd ⊢ φ → X 2 nd ⁡ F G Y = X G Y
17 eqidd ⊢ φ → X H Y = X H Y
18 3 func1st ⊢ φ → 1 st ⁡ F G = F
19 18 fveq1d ⊢ φ → 1 st ⁡ F G ⁡ X = F ⁡ X
20 18 fveq1d ⊢ φ → 1 st ⁡ F G ⁡ Y = F ⁡ Y
21 19 20 oveq12d ⊢ φ → 1 st ⁡ F G ⁡ X J 1 st ⁡ F G ⁡ Y = F ⁡ X J F ⁡ Y
22 16 17 21 f1eq123d ⊢ φ → X 2 nd ⁡ F G Y : X H Y ⟶ 1-1 1 st ⁡ F G ⁡ X J 1 st ⁡ F G ⁡ Y ↔ X G Y : X H Y ⟶ 1-1 F ⁡ X J F ⁡ Y
23 4 func2nd ⊢ φ → 2 nd ⁡ K L = L
24 23 19 20 oveq123d ⊢ φ → 1 st ⁡ F G ⁡ X 2 nd ⁡ K L 1 st ⁡ F G ⁡ Y = F ⁡ X L F ⁡ Y
25 24 21 17 foeq123d ⊢ φ → 1 st ⁡ F G ⁡ X 2 nd ⁡ K L 1 st ⁡ F G ⁡ Y : 1 st ⁡ F G ⁡ X J 1 st ⁡ F G ⁡ Y ⟶ onto X H Y ↔ F ⁡ X L F ⁡ Y : F ⁡ X J F ⁡ Y ⟶ onto X H Y
26 22 25 anbi12d ⊢ φ → X 2 nd ⁡ F G Y : X H Y ⟶ 1-1 1 st ⁡ F G ⁡ X J 1 st ⁡ F G ⁡ Y ∧ 1 st ⁡ F G ⁡ X 2 nd ⁡ K L 1 st ⁡ F G ⁡ Y : 1 st ⁡ F G ⁡ X J 1 st ⁡ F G ⁡ Y ⟶ onto X H Y ↔ X G Y : X H Y ⟶ 1-1 F ⁡ X J F ⁡ Y ∧ F ⁡ X L F ⁡ Y : F ⁡ X J F ⁡ Y ⟶ onto X H Y
27 14 26 mpbid ⊢ φ → X G Y : X H Y ⟶ 1-1 F ⁡ X J F ⁡ Y ∧ F ⁡ X L F ⁡ Y : F ⁡ X J F ⁡ Y ⟶ onto X H Y