Metamath Proof Explorer


Theorem cofu1a

Description: Value of the object part of the functor composition. (Contributed by Zhi Wang, 16-Nov-2025)

Ref Expression
Hypotheses cofu1a.b ⊢ B = Base C
cofu1a.f ⊢ φ → F C Func D G
cofu1a.k ⊢ φ → K D Func E L
cofu1a.m ⊢ φ → K L ∘ func F G = M N
cofu1a.x ⊢ φ → X ∈ B
Assertion cofu1a ⊢ φ → K ⁡ F ⁡ X = M ⁡ X

Proof

Step Hyp Ref Expression
1 cofu1a.b ⊢ B = Base C
2 cofu1a.f ⊢ φ → F C Func D G
3 cofu1a.k ⊢ φ → K D Func E L
4 cofu1a.m ⊢ φ → K L ∘ func F G = M N
5 cofu1a.x ⊢ φ → X ∈ B
6 df-br ⊢ F C Func D G ↔ F G ∈ C Func D
7 2 6 sylib ⊢ φ → F G ∈ C Func D
8 df-br ⊢ K D Func E L ↔ K L ∈ D Func E
9 3 8 sylib ⊢ φ → K L ∈ D Func E
10 1 7 9 5 cofu1 ⊢ φ → 1 st ⁡ K L ∘ func F G ⁡ X = 1 st ⁡ K L ⁡ 1 st ⁡ F G ⁡ X
11 4 fveq2d ⊢ φ → 1 st ⁡ K L ∘ func F G = 1 st ⁡ M N
12 7 9 cofucl ⊢ φ → K L ∘ func F G ∈ C Func E
13 4 12 eqeltrrd ⊢ φ → M N ∈ C Func E
14 df-br ⊢ M C Func E N ↔ M N ∈ C Func E
15 13 14 sylibr ⊢ φ → M C Func E N
16 15 func1st ⊢ φ → 1 st ⁡ M N = M
17 11 16 eqtrd ⊢ φ → 1 st ⁡ K L ∘ func F G = M
18 17 fveq1d ⊢ φ → 1 st ⁡ K L ∘ func F G ⁡ X = M ⁡ X
19 3 func1st ⊢ φ → 1 st ⁡ K L = K
20 2 func1st ⊢ φ → 1 st ⁡ F G = F
21 20 fveq1d ⊢ φ → 1 st ⁡ F G ⁡ X = F ⁡ X
22 19 21 fveq12d ⊢ φ → 1 st ⁡ K L ⁡ 1 st ⁡ F G ⁡ X = K ⁡ F ⁡ X
23 10 18 22 3eqtr3rd ⊢ φ → K ⁡ F ⁡ X = M ⁡ X